Binomial Coefficient Equivalency

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SUMMARY

The discussion centers on finding an expression equivalent to the summation \(\sum_{k=0}^n \binom{3n}{3k}\). The solution provided by Wolfram is \(\frac{1}{3} \left(2(-1)^n + 8^n\right)\). Participants express uncertainty about which binomial coefficient identities to apply for proof and consider using mathematical induction to verify Wolfram's result, although they encounter challenges in expanding the binomial coefficients from the \(n-1\) to \(n\) case.

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  • Understanding of binomial coefficients and their properties
  • Familiarity with mathematical induction techniques
  • Knowledge of summation notation and series
  • Experience with combinatorial identities
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  • Study binomial coefficient identities, particularly those related to \(\binom{3n}{3k}\)
  • Learn about mathematical induction proofs in combinatorics
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Find an expression that is identical to \sum_{k=0}^n \binom{3n}{3k}

According to Wolfram, the correct solution to this is: \frac{1}{3} \left(2(-1)^n + 8^n\right)

But I'm not sure which identities of the binomial coefficient I'm supposed to use to prove this. Can anyone give me some direction?

Thanks!
 
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Does nobody have any ideas? I was wondering if it were possible to confirm Wolfram's answer via induction, but expanding the resulting binomial coefficients fron the n-1 to the n case is proving to be fairly difficult. Any help is appreciated.
 

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