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Introductory Physics Homework Help
Why Does Calculating Binomial Probabilities Differ from Simple Outcome Ratios?
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[QUOTE="Pushoam, post: 5838855, member: 619344"] [h2]Homework Statement [/h2] [ATTACH=full]210844[/ATTACH] [ATTACH=full]210841[/ATTACH] I am not getting the above. Let me calculate the probability of getting 2 successes from 5 Bernoulli trials. There are total 10 possible outcomes as each trial has two possible outcomes. The probability of getting one success is P(S1) = No. of successes / no. of total possible outcomes = 5/10 = 1/2 The probability of getting another success = No. of successes / no. of total possible outcomes = 4/9 So, the probability of getting two successes = 1/2(4/9)= 2/9 This doesn't match the answer given by the binomial distribution formula. So, what is wrong here? [ATTACH=full]210842[/ATTACH] [B]I couldn't understand how is binomial distribution sum of n independent Bernoulli trials?[/B] If I denote ith trial by ##X_i ##, then how can k i.e. no. of successes be sum of the trials i.e.∑##_i X_i##? [h2]Homework Equations[/h2][h2]The Attempt at a Solution[/h2] [/QUOTE]
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Why Does Calculating Binomial Probabilities Differ from Simple Outcome Ratios?
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