MHB Binomial Experiments: Find Probability of x=5, x>=6, x<4

aprilryan
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Hi all,

I'm a bit confused on this problem in my book.

"Specify the values of n, p, and q and list the possible values of the random variable x.
Sixty percent of U.S. adults trust national newspapers to present the news fairly and accurately. You randomly select nine U.S. adults. Find the probability that the number of U.S. adults who trust national newspapers to present the news fairly and accurately is (a) exactly five, (b) at least six, and (c) less than four."

I have the values.

n=9
p=.63
q=.37
x=5
x is at least six
x<4

Would I have to do them on the calculator using binomial pdf and sum commands or find the mean, standard deviation and variance?

Note: I have been shown to do these types of problems on the calculator using the binomial pdf and sum commands.
 
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aprilryan said:
Hi all,

I'm a bit confused on this problem in my book.

"Specify the values of n, p, and q and list the possible values of the random variable x.
Sixty percent of U.S. adults trust national newspapers to present the news fairly and accurately. You randomly select nine U.S. adults. Find the probability that the number of U.S. adults who trust national newspapers to present the news fairly and accurately is (a) exactly five, (b) at least six, and (c) less than four."

I have the values.

n=9
p=.63
q=.37
x=5
x is at least six
x<4

Would I have to do them on the calculator using binomial pdf and sum commands or find the mean, standard deviation and variance?

Note: I have been shown to do these types of problems on the calculator using the binomial pdf and sum commands.

Where does $p = 0.63$ comes from? I would say it should be $p=0.6$ according to the question.
 
Yes, it was .60. Thanks, I've got this one figured out!
 
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