Binomial Theorem Homework Help: 3/2 in Parentheses?

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The discussion revolves around understanding the binomial coefficient, specifically the expression 3C2, which represents the number of ways to choose 2 items from 3. Participants clarify that the binomial coefficient is calculated using the formula n!/(r!(n-r)!), and they address confusion regarding the first term, particularly the calculation involving 0!. It is established that 0! equals 1, resolving the issue of undefined values in the context of the binomial theorem. Ultimately, the participants confirm their understanding of the binomial coefficients and how to apply them correctly. This clarification aids in solving the homework problem effectively.
g.lemaitre
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Homework Statement



Screenshot2012-06-26at12743AM.png



What am I supposed to do with the 3 over 2 in the parentheses? It can be divide and it can be take the factorial. So what do I do with it?
 
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Hi g.lemaitre :smile:

g.lemaitre said:

Homework Statement



Screenshot2012-06-26at12743AM.png



What am I supposed to do with the 3 over 2 in the parentheses? It can be divide and it can be take the factorial. So what do I do with it?

It is the number of ways of choosing 2 items out of 3 different items. In other words, combinations.

3C2.
 
Hi Infinitum! Call me Georges.

Does that mean you take 3!/2!? That work for the 3rd and 4th term but not for the second term and for the first term I think it's undefined.
 
g.lemaitre said:
Hi Infinitum! Call me Georges.

Does that mean you take 3!/2!? That work for the 3rd and 4th term but not for the second term and for the first term I think it's undefined.

Okay, Georges then.

The binomial coefficient is given as,

\binom{n}{r} = \frac{n!}{r!(n-r)!}

Where, 0 \leq r \leq n

Why do you think this isn't defined for the first term??
 
Man, infinitum, you're such a big number it takes me like forever just to count you.

I understand the binomial coefficient and can get the right answer for terms 2 3 and 4 but I'm still having trouble with the first term.

if
\binom{n}{r} = \frac{n!}{r!(n-r)!}

then

\binom{3}{0} = \frac{3!}{0!(3-0)!} = \frac{6}{0}
 
g.lemaitre said:

Homework Statement



Screenshot2012-06-26at12743AM.png


What am I supposed to do with the 3 over 2 in the parentheses? It can be divide and it can be take the factorial. So what do I do with it?
The binary coefficient, \displaystyle \binom nk is defined as follows.

\displaystyle \binom nk = \frac{n!}{k!\,(n-k)!}\ , \quad \mbox{for }\ 0\leq k\leq n
 
g.lemaitre said:
Man, infinitum, you're such a big number it takes me like forever just to count you.

I understand the binomial coefficient and can get the right answer for terms 2 3 and 4 but I'm still having trouble with the first term.

if
\binom{n}{r} = \frac{n!}{r!(n-r)!}

then

\binom{3}{0} = \frac{3!}{0!(3-0)!} = \frac{6}{0}

0! (zero factorial) is not equal to 0...

See the summary of this article : https://www.physicsforums.com/showthread.php?t=530207
 
Last edited by a moderator:
thanks, i got it now.
 
zero factorial equals one.
 

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