googlymunja32 Messages 4 Reaction score 0 Thread starter Sep 10, 2008 #1 kx = x !/r! (x – r)! kx− r is that right?
mathman Science Advisor Homework Helper Messages 8,130 Reaction score 575 Sep 10, 2008 #2 googlymunja32 said: kx = x !/r! (x – r)! kx− r is that right? The right side of your equation is confusing. Put in some parentheses.
googlymunja32 said: kx = x !/r! (x – r)! kx− r is that right? The right side of your equation is confusing. Put in some parentheses.
googlymunja32 Messages 4 Reaction score 0 Sep 10, 2008 #3 see attachment - Attachments untitled.JPG 7.2 KB · Views: 397
mathman Science Advisor Homework Helper Messages 8,130 Reaction score 575 Sep 11, 2008 #4 The thunbnail is hard to read. In the second equation there are terms with k to some exponent. It is hard to read these exponents. Also, what is the question - prove the second equation holds?
The thunbnail is hard to read. In the second equation there are terms with k to some exponent. It is hard to read these exponents. Also, what is the question - prove the second equation holds?