Bird Flying Speed at 10m Altitude

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SUMMARY

The discussion centers on calculating the horizontal speed of a bird flying at an altitude of 10 meters, with an angular change of 0.5 rad/s. The relationship between the angle of elevation and horizontal distance is defined by the equation $\cot{\theta} = \dfrac{x}{10}$. By differentiating this equation implicitly with respect to time and evaluating at $\theta = \dfrac{\pi}{2}$, the horizontal speed $\dfrac{dx}{dt}$ can be determined. This analysis provides a clear mathematical framework for understanding the bird's speed at the moment it is directly overhead.

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Jimmy Perdon
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A bird is flying at an altitude of 10m above you, his angular position from your point of view is changing at 0.5 rad · s^-1. How fast is the bird flying when he is directly above you?
 
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have you made a sketch? if so, do you see this relationship?

$\cot{\theta} = \dfrac{x}{10}$

where $\theta$ is the angle of elevation from the observer to the bird, and $x$ is the horizontal distance from the observer to the bird.

you are given $\dfrac{d\theta}{dt}$

differentiate implicitly with respect to time and determine $\dfrac{dx}{dt}$ when $\theta = \dfrac{\pi}{2}$
 
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Thank you!
 

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