MHB Bird Flying Speed at 10m Altitude

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The discussion centers on calculating the horizontal speed of a bird flying at 10m altitude, given its angular change of 0.5 rad/s from an observer's point of view. The relationship between the angle of elevation and horizontal distance is expressed using the cotangent function. By differentiating the equation implicitly with respect to time, the aim is to find the horizontal speed when the bird is directly overhead, at an angle of π/2. The conversation emphasizes the importance of visualizing the problem through sketches to understand the relationship better. Ultimately, the calculation seeks to determine the bird's speed at that specific moment.
Jimmy Perdon
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A bird is flying at an altitude of 10m above you, his angular position from your point of view is changing at 0.5 rad · s^-1. How fast is the bird flying when he is directly above you?
 
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have you made a sketch? if so, do you see this relationship?

$\cot{\theta} = \dfrac{x}{10}$

where $\theta$ is the angle of elevation from the observer to the bird, and $x$ is the horizontal distance from the observer to the bird.

you are given $\dfrac{d\theta}{dt}$

differentiate implicitly with respect to time and determine $\dfrac{dx}{dt}$ when $\theta = \dfrac{\pi}{2}$
 
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Thank you!