- #1

TaxiDriver113

- 2

- 0

## Homework Statement

A 3 kg block is held against a spring (k=580nt/m) at the bottom of a frictionless 25 degree incline. The spring is compressed 0.18m. How far along the incline does the block go when released.

## Homework Equations

Usp=1/2kx^2

## The Attempt at a Solution

So far the only thing I've been able to do was calculate the velocity which i got to be 1.65m/s if I did it correctly.

Usp= 1/2 * 580 * .18^2

= 9.396

then I did this equation but I didn't know exactly what h was that I was trying to calculate. I think i just ended up calculating how much the spring was compressed and I already knew that.

9.396 + (1/2)(3)(0) = (3)(9.8)(h) + (1/2)(3)(1.654^2)

9.396 = 29.4h + 4.103

h = .18

Last edited: