The discussion revolves around a problem involving a 400 cm³ block of aluminum being lowered into a full beaker of water, specifically focusing on determining the weight of the water that spills out due to the displacement caused by the block.
Some participants have provided calculations and insights regarding the mass of the displaced water, while others express confusion about their own calculations. There is an acknowledgment of differing results, but no consensus has been reached on the correct approach or outcome.
Participants are working under the constraints of the problem statement and are questioning their assumptions regarding the calculations of mass and weight, as well as the implications of the block's volume on the displaced water.
test2morrow said:Homework Statement
A 400 cm^3 block of aluminum (D=2.7 g/cm^3) is lowered into a completely full beaker of water. What is weight of water that spills out of the beaker? Correct answer is 4N.
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When 400 cm^3 block of aluminum is completely lowered in the water, 400 cm^3 of water is spilled out. Its mass is 400 g or 0.4 kg. Find the weight of this water.