Block move down the curved hill and hit attached block spring

Click For Summary
SUMMARY

A 100-gram block moving at 2 m/s down a curved hill collides elastically with a stationary 400-gram block attached to a spring with a spring constant of 500 N/m. To find the maximum distance the spring compresses and the maximum height the 100-gram block reaches post-collision, one must apply the conservation of momentum and energy principles. The relevant equations include m1u1 + m2u2 = m1v1 + m2v2 for momentum and F = kx for spring compression. A diagram illustrating the scenario is recommended for clarity.

PREREQUISITES
  • Understanding of conservation of momentum
  • Familiarity with elastic collisions
  • Knowledge of spring mechanics and Hooke's Law
  • Ability to perform energy conservation calculations
NEXT STEPS
  • Calculate the final velocities of both blocks after the collision using conservation of momentum.
  • Determine the maximum compression of the spring using the formula F = kx.
  • Analyze the energy transfer to find the maximum height of the 100-gram block after the collision.
  • Create a diagram of the scenario to visualize the problem better.
USEFUL FOR

Physics students, educators, and anyone studying mechanics, particularly those interested in elastic collisions and energy conservation principles.

cecico
Messages
15
Reaction score
0
A 100grams block is moving at 2m/s down the curved hill. The block slides along the smooth surface and collides elastically with the 400gram block. The 400gram block is initially at rest and is attached to an ideal spring with spring constant of 500N/m
a)Find the maximum distance the spring compresses
b)Find the maximum height the 100gram block reaches after the collision.

I have no idea with this problem...someone help me...
 
Physics news on Phys.org
Conservation of energy.
Give that a go - let us know what happens.
 
In order to receive help with this problem I suggest that you

a) Provide a diagram
b) Show the work you have tried thus far. Forum rules.
 
dont know for sure but collisions usually go by the equation

m1u1 + m2u2 = m1v1 +m2v2

m1 being mass 1 = 0.1kg
m2 being 0.4 kg

u1 being =2 m/s
u2 = 0 m/s as its stationary

then work out the momentum of the second block as this would be equal to the force on the spring which would follow the equation

F = kx

where k is 500 N/m and thus u have the distance x

and then its pray someone with more brains than me gives u an answer otherwise ul b stuck on it all night long...lol...sorry mate
 
how to post diagram?
 
cecico said:
how to post diagram?

Scanner, photograph, MS Paint. Free account at Photobucket.com will host images.
I know it's a little work... but it will get your question answered much quicker.
 

Similar threads

Replies
20
Views
6K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 12 ·
Replies
12
Views
3K
Replies
24
Views
4K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
3
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
2
Views
1K
Replies
11
Views
3K