Block Slides on Rough Horiz Surface with Pic

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SUMMARY

A block slides on a rough horizontal surface from point A to point B, with a force of 2 Newtons acting on it. The initial kinetic energy (KE) at point A is 5 joules, and at point B, it is 4 joules. The work done by friction as the block moves from A to B is calculated using the Work-Energy Theorem, which states that the change in KE equals the sum of the work done by all forces. The correct calculation reveals that the work done by friction is -3.298 joules.

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Homework Statement


A block slides on a rough horizontal surface from point A to point B with a force of magnitude 2 Newtons acts on the block between points A and B. Points A and B are 1.5m apart. If the KE of the block at A is 5 joules, and KE at B is 4J, how much work is done on the block by the force of friction as the block moves from A to B

my crude rendering of said block:

http://img69.imageshack.us/img69/2411/30326150.th.png


Homework Equations



change in E mechanical=Work done by other forces - Force of friction * distance

The Attempt at a Solution



change in KE = Force * distance + Work done by friction
-1 = 2 cos 40 * 1.5 + Work done by friction
-1 = 2.29813 + Work done by friction
-3.298J = Work done by friction
is this correct?
i got -3.298J
 
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hodgepodge said:
change in KE = Force * distance + Work done by friction

This equation is incorrect. The correct equation (Work-Energy Theorem) says

Change in KE = Sum of the work done by all the forces.

How many forces are doing work and what is the work done by each force? Call the unknown work done by friction Wf, write the Work-Energy Theorem correctly and solve for the unknown Wf.
 

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