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## Homework Statement

A block with a mass of 4 kg slides from rest a distance of 2 m down a frictionless inclined plane where it encounters a spring. It compresses the spring a distance 1.4 m before stopping. The inclined plane makes an angle q = 35° with the horizontal. What is the value of the spring constant?

## Homework Equations

F=-kx

F=MA

## The Attempt at a Solution

First, the force on the block = Mass (4) times acceleration. (9.81)

The force of the block when it touches the spring is 39.24.

So, the force the spring exerts is equal and opposite.

39.24 = -kx

X=1.4, so it should be easy:

39.24 = -k 1.4

-k = 28.028

k = -28.028

But this is not right...