Blocks are connected by thin strings with tensions

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SUMMARY

The discussion focuses on calculating the tension Tz in a system of four blocks connected by strings, subjected to two external forces, F1=47.0N and F2=71.0N. The total mass of the blocks is 130 kg, leading to an acceleration of 0.1846 m/s². The initial calculation for Tz was incorrect; the correct approach involves using the equations Tz - F1 = 130 * 0.1846 and Tz - Ty = 39 * 0.1846 to derive the accurate tension values. The final tension Tz is determined by first calculating Ty from the equation Ty - F1 = 29 * 0.1846.

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  • Understanding of Newton's Second Law (F=ma)
  • Basic knowledge of tension in strings and forces
  • Ability to perform calculations involving mass, force, and acceleration
  • Familiarity with systems of equations in physics
NEXT STEPS
  • Calculate the tension Ty using the equation Ty - F1 = 29 * 0.1846
  • Determine the correct value of Tz using Tz - Ty = 39 * 0.1846
  • Explore the effects of friction on tension calculations in similar systems
  • Review concepts of static and dynamic equilibrium in multi-block systems
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Students studying physics, particularly those focusing on mechanics and tension in systems, as well as educators looking for practical examples of force and tension calculations.

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Homework Statement



Four blocks are on a horizontal surface.
<---F2---B---Tx---A---Tz---D----Ty--C---F1-->

The blocks are connected by thin strings with tensions Tx, Ty, Tz. The masses of the blocks are A=41.0 kg, B=21.0 kg, C=29.0 kg, D=39.0 kg. Two forces, F1=47.0N and F2=71.0N act on the masses as shown. Assume that the friction between the masses and the surface is negligible and calculate the tension Tz.


Homework Equations



F=ma



The Attempt at a Solution



I calculated the total mass =130 kg
Total force 71-47= 24 N
Then the acceleration F/m=0.1846 m/s^2
Next I calculated the Tension in Tz by :
Tz -F1 = 130 * 0.1846
I got 70.9 N

I'm not sure if that's correct??
 
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NikkiNik said:

Homework Statement



Four blocks are on a horizontal surface.
<---F2---B---Tx---A---Tz---D----Ty--C---F1-->

The blocks are connected by thin strings with tensions Tx, Ty, Tz. The masses of the blocks are A=41.0 kg, B=21.0 kg, C=29.0 kg, D=39.0 kg. Two forces, F1=47.0N and F2=71.0N act on the masses as shown. Assume that the friction between the masses and the surface is negligible and calculate the tension Tz.

Homework Equations



F=ma

The Attempt at a Solution



I calculated the total mass =130 kg
Total force 71-47= 24 N
Then the acceleration F/m=0.1846 m/s^2
Next I calculated the Tension in Tz by :
Tz -F1 = 130 * 0.1846
I got 70.9 N

I'm not sure if that's correct??

Not quite. You have the acceleration of the system. That's a start.

Now you need to figure the internal forces, you know like block 1 times acceleration is presenting a force, block 2 times acceleration ... etc. Then you can determine the tension in the middle cord.
 


Tz -F1 = 130 * 0.1846 It is not correct.
From Ty -F1 = 29 * 0.1846 find Ty
From Tz - Ty = 39 * 0.1846 Find Tz
 

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