Three Blocks Connected Concepts

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Jack Arnett
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Unsure what or which answers are incorrect.

1. Homework Statement

In the figure below, assume that the pulleys are massless and frictionless.
**Attached File**
The masses of the blocks are Ma=1.50 kg, Mb=4.00 kg, Mc=6.00 kg, and there is friction between the horizontal plane and Mc, (μk≠0). Mc is observed to travel at a constant velocity.

True, False, Greater than, Less Than, or Equal to
Tx is ... Ty
Mc is moving to the right
Ma*g is ... Tz.
The magnitude of the total force on Mc is ... 0
Mb accelerates downward
Tz is ... Ty

Homework Equations


Tz=Tw
Ty=Tx

The Attempt at a Solution


I've got it answered as.
Tx is EQUAL to Ty
Mc is moving to the right TRUE
Ma*g is LESS THAN Tz.
The magnitude of the total force on Mc is EQUAL TO 0
Mb accelerates downward TRUE
Tz is LESS THAN Ty
 

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Jack Arnett said:

The Attempt at a Solution


I've got it answered as.
Tx is EQUAL to Ty
Mc is moving to the right TRUE
Ma*g is LESS THAN Tz.
The magnitude of the total force on Mc is EQUAL TO 0
Mb accelerates downward TRUE
Tz is LESS THAN Ty

Some of these are incorrect.

"Mc is observed to travel at a constant velocity"

What does this imply about the motion of Ma and Mb?
And what does the mean about the sum of the forces on Ma & Mb?
 
billy_joule said:
Some of these are incorrect.

"Mc is observed to travel at a constant velocity"

What does this imply about the motion of Ma and Mb?
And what does the mean about the sum of the forces on Ma & Mb?

The motion as in Ma will rise and Mb will fall? Also meaning the force on Mb is greater than Ma?
 
.
 
Last edited:
Honestly I just need the answer, I'm running out of time.
 
Imagine a truck towing a trailer, can the truck go at constant velocity and the trailer be accelerating? Can the trailer go faster or slower than the truck?

Masses A,B & C are connected. Unless otherwise stated always assume that string does not stretch or go slack. In other words, the velocity and acceleration of all three blocks is equal.
 
Yes, I'm still very confused which answer you offering hints for which are incorrect
 
This is an unacceptable response on Physics Forums.
Well you were no help...
 
Please see the rules:
https://www.physicsforums.com/threads/physics-forums-global-guidelines.414380/

Particularly these parts:
  • Full solutions on a homework problem should never be given. Only hints and explanations are allowed.

  • Giving Full Answers:
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Also, it's generally considered bad manners to edit/remove posts. It makes the thread harder for others to follow (and less likely to help..).