Bob's Acceleration and Angle with the Vertical on an Inclined Plane

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SUMMARY

The discussion revolves around determining the angle a bob makes with the vertical while suspended from a frame sliding down an inclined plane. The key conclusion is that the angle phi (φ) made by the bob with the vertical is equal to the angle theta (θ) of the inclined plane. The acceleration of the frame is calculated as g*sin(θ), where g represents gravitational acceleration. Understanding the forces acting on the bob, including the vertical force m*g and the acceleration due to the frame's motion, is crucial for solving the problem.

PREREQUISITES
  • Understanding of Newton's second law (F=ma)
  • Knowledge of gravitational acceleration (g)
  • Familiarity with inclined plane dynamics
  • Basic trigonometry for angle relationships
NEXT STEPS
  • Study the dynamics of inclined planes in physics
  • Learn about forces acting on objects in non-inertial frames
  • Explore the concept of tension in pendulum systems
  • Investigate the relationship between angles and forces in static equilibrium
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators seeking to clarify concepts related to inclined planes and pendulum motion.

Frillth
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Homework Statement



A bob suspended from a frame settles into a steady position relative to the frame as the frame slides down an inclined plane. What angle does the bob make with the during the slide?

Here is the illustration from the book:
http://img237.imageshack.us/img237/9803/plumbbobfs4.jpg

Homework Equations



Unknown. F=ma?

The Attempt at a Solution



I don't really have any idea how to start this problem. I thought the first step would be to calculate that the acceleration of the frame = g*sin(theta), but I don't really know where to go from there. Any ideas?
 
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I left a word out in my original post. It should have said, "What angle does the bob make with the VERTICAL during the slide?"

Also, I found out that the solution is phi = theta, if that would help with working backwards.
 
Frillth said:
I left a word out in my original post. It should have said, "What angle does the bob make with the VERTICAL during the slide?"

Also, I found out that the solution is phi = theta, if that would help with working backwards.

What is the acceleration of the "frame" in which the bob hangs?

As you noted it is M*g*Sinθ for the force so acceleration of the frame must be g*Sinθ .

Now what force is acting on the bob? There is the vertical force m*g acting straight down. What other acceleration is the bob subjected to?
 

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