BOD (biochemical oxygen demand) calculation

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SUMMARY

The discussion centers on calculating the biochemical oxygen demand (BOD) for meat-processing wastewater with an initial strength of 800 mg/L. The BOD calculation utilizes the formula BODt = [(DOi - DOf) - (Bi - Bf)(1-P) / P], where initial and final dissolved oxygen (DO) levels are provided. The initial DO for both seed and sample bottles is 8.5 mg/L, with final DOs of 4.5 mg/L for the seed and 3.5 mg/L for the wastewater sample. A critical point raised is the absence of the dilution factor (P), which is essential for completing the calculation.

PREREQUISITES
  • Understanding of biochemical oxygen demand (BOD) calculations
  • Knowledge of dissolved oxygen (DO) measurements
  • Familiarity with wastewater treatment processes
  • Basic algebra for manipulating equations
NEXT STEPS
  • Research the significance of the dilution factor (P) in BOD calculations
  • Learn about the methods for measuring dissolved oxygen in wastewater
  • Explore the implications of BOD in wastewater treatment efficiency
  • Study the differences between seeded and unseeded BOD tests
USEFUL FOR

Environmental engineers, wastewater treatment professionals, and students studying water quality management will benefit from this discussion.

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Homework Statement


A seeded BOD test is to be conducted on meat-processing wastewater with an estimated strength of 800 mg/L. The seed is supernatant from aged, settled, domestic wastewater with BOD of about 150 mg/L. Calculate the BOD value for the industrial wastewater if the initial DO in both seed and sample bottles is 8.5 mg/L and the 5-day DOs are 4.5 mg/L and 3.5 mg/L for the seed test bottle and seeded waste water samples respectively.

Homework Equations

The Attempt at a Solution


BODt = [( DOi - DOf ) - ( Bi - Bf)(1-P) / P ]
Bi = initial DO concentration of seeded diluted water
Bf = final DO concentration of seeded diluted water
DOi = initial DO concentration of diluted sample
DOf = final DO concentration of diluted sample
P = Volume sample / total volume

I think the question can't be done , because the dilution factor (P) isn't given . Correct me if I am wrong ...[/B]
 
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Anyone has idea ?
 

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