Boltzmann collision term irreversibility

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SUMMARY

The discussion centers on the Boltzmann collision term and its role in demonstrating irreversibility in statistical mechanics. Michel emphasizes the importance of deriving the H theorem from the Boltzmann equation to establish the non-symmetry of the collision term under time reversal. He suggests finding an equilibrium distribution, specifically feq~exp[-(p-p0)²], where p0 represents the average momentum of gas particles, to show that the collision term is zero. The conversation highlights the necessity of constraining the vector q to ensure that only the angle of relative velocity changes during collisions.

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  • Understanding of the Boltzmann equation
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  • Knowledge of equilibrium distributions in kinetic theory
  • Basic principles of particle collisions and momentum
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Physicists, particularly those specializing in statistical mechanics, researchers studying kinetic theory, and students seeking to understand the principles of irreversibility in thermodynamics.

lalbatros
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Hello,

Here is the Boltzmann collision term as it is expressed on http://en.wikipedia.org/wiki/Boltzmann_equation" :

e8a8831287922e311a172221dd8d1efa.png


Deriving the H theorem from this equation is the way to usually prove of the irreversibility of this term.
Of course, this collision term should not be symmetric by time reversal.
I guess it is easy to prove that without recourse to the H theorem.
How could I do (see) that?

Thanks,

Michel
 
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First find an equilibruim distribution feq such that the collision term is zero. Next show that the sign of the collision term is the opposite of any deviation of f from feq so that f restores back to feq.
To start off, show that the collision term is zero for feq~exp[-(p-p0)2]. Where p0 is a constant average momentum of the gas (in dimensionless units scaled by sqrt(2 m Eavg) ). p0could be set to zero for simplicity); m is mass of the particles.
Keep in mind that the vector q must be constrained so that only the angle of the relative velocity changes during a collision.
 
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