Boltzmann constant in formulas

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SUMMARY

The Boltzmann constant (k) is presented in two primary forms: k = 8.62 x 10-5 eV/K and k = 1.38 x 10-23 J/K. When calculating intrinsic carrier concentration (ni), it is essential to ensure that the units of kT match those of the energy term Eg(T). For example, if Eg(T) is expressed in electron volts (eV), then kT must also be in eV. Additionally, the noise power formula kTB, where T is temperature in Kelvin and B is bandwidth in Hz, yields a noise power of approximately -111 dBm per MHz at room temperature (293 K).

PREREQUISITES
  • Understanding of the Boltzmann constant and its forms (eV/K and J/K)
  • Familiarity with intrinsic carrier concentration formulas
  • Knowledge of noise power calculations in electronics
  • Basic principles of thermodynamics and statistical mechanics
NEXT STEPS
  • Study the derivation of the intrinsic carrier concentration formula ni = sqrt(NcNv) e-Eg(T)/2kT
  • Learn about the significance of the Boltzmann constant in semiconductor physics
  • Explore the relationship between temperature and energy in the context of kT
  • Investigate the implications of noise figure in electronic systems
USEFUL FOR

Physicists, electrical engineers, and students studying semiconductor physics or thermodynamics will benefit from this discussion, particularly those interested in the applications of the Boltzmann constant in formulas and noise power calculations.

aarnes
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Hi, I see that Boltzmann constant comes in different forms like: k=8.62*10-5 eV/K and also k=1.38*10-23J/K.
Which one should I use in , say formula for intrinsic carrier concentration ni = sqrt(Nc*Nv)*e-Eg(T)/2kT ?
 
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kT has units of energy; Joules or electron volts. Always remember that an exponent has to be unitless. If the numerator has volts, then kT is in eV.

Sometimes you will see kTB which is noise power times bandwidth.

The noise power is kTB where k= 1.38 x 10-20 millijoules per deg kelvin, T=293 kelvin, and B(bandwidth in Hz)= 1 MHz

So noise power is 1.38 x 10-20 x 293 x 106 Hz= 4 x 10-12milliwatts per MHz = -114 dBm per MHz.

Add 3 dB noise figure to get -111 dBm per MHz
 
Last edited:
Thank you, Bob! I used the eV form before but I saw some different results on the web and just wasn't sure why is there always a slightly different value for ni, depending on which website you look.
 
Instead of k_ B = 8.62 \times 10^{-5} \, \frac{\mathrm{eV}}{\mathrm{K}}, people usually find it convenient to remember the following number:
<br /> k_B = \frac{1 \, \mathrm{eV}}{11600 \, \mathrm{K}}<br />

(notice that (8.62 \times 10^{-5})^{-1} = 1.16 \times 10^4, so the above are equivalent)
 
At room temperature T \approx 293 \, \mathrm{K}, the value k_B \, T \approx 25 \, \mathrm{meV}.
 
Dickfore said:
At room temperature T \approx 293 \, \mathrm{K}, the value k_B \, T \approx 25 \, \mathrm{meV}.

On the web you usually see 300K as room temperature. I guess it depends on one's preference? :D
 
aarnes said:
On the web you usually see 300K as room temperature. I guess it depends on one's preference? :D

Right, that is why i used only 2 significant figures in the final result and the approximate sign.
 
aarnes said:
Hi, I see that Boltzmann constant comes in different forms like: k=8.62*10-5 eV/K and also k=1.38*10-23J/K.
Which one should I use in , say formula for intrinsic carrier concentration ni = sqrt(Nc*Nv)*e-Eg(T)/2kT ?


boy, you sure are good at using HTML markup. i never knew you could get a subscript in the superscript. anyway, it might look better with LaTeX

n_i \ = \ \sqrt{N_c N_v} e^{-\frac{E_g(T)}{2 k T}}


now, to answer your question, you want you kT quantity to be in the same units as the E_g quantity. if k=8.62 \times 10^5 eV/K then T better be in Kelvin and E_g better be in eV.
 

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