1. The problem statement, all variables and given/known data A spring of negligible mass has force constant K = 1700 n/m A book of mass 1.30 kg is dropped from a height of .7m above the top of the spring. Find the maximum distance the spring will be compressed. 2. Relevant equations PEi + KEi = PEf + KEf PEgrav = mgy PEspring = 1/2Kx2 KEbook = 1/2Mv2 V=\sqrt [V2initial + 2 8 (9.8) *(.7)] = 3.70405 m/s approx 3. The attempt at a solution I have tried this various ways without success. I think that I have the equation incorrect. I have: PEi + KEi = PEf + KEf PEgrav i + PEspring i + KEbook i = KEbook f + PEgrav f + PEspring f mgy + 0 + 0 = 1/2Mv2 + 0 + 1/2Kx2 1.3 * 9.8 * .7 = 1/2 * 1.3 * 13.72 (which is v^2) + 0 + 1/2 * 1700 * x^2 8.918 = 8.918 + 850 x^2 which gives me 0 I know that I am missing something here The first part of this question asks : How far must the spring be compressed for an amount 3.50 J of potential energy to be stored in it? Which I solved by using Uel = 1/2Kx2 but for some reason it is not working for the second part. The book is exerting a force of mgy 1.3*9.8*.7 on the spring and I should be able to set that equal to 1/2Kx2 but it was not correct. Can someone tell me what I am missing here? Sorry this is long I tried to be detailed with what I have so far.