Boole vs. Bell - the latest paper of De Raedt et al

  • Thread starter harrylin
  • Start date
  • Tags
    Bell Paper
In summary: COMPLETE description of the paper's content would be completely wrong and would not be useful to summarise it. In summary, the De Raedt paper discusses the apparent contradictions of quantum theory and probability frameworks, and argues that these contradictions arise from incomplete considerations of the premises of the derivation of the inequalities. They present extended Boole-Bell inequalities which are binding for both classical and quantum models, and show that apparent violations of these inequalities can be explained in an Einstein local way.
  • #71
DrChinese said:
That is the OPPOSITE of the EPR argument, which was: that individual elements of reality exist simultaneously, and that the possibility of specifying same proves QM is incomplete..

No. My definition of realism is consistent with the EPR one. If you disagree, provide a quote from EPR which shows otherwise

If, without in anyway disturbing a system, we can predict with certainty (...) the value of a physical quantity, then there exists an element of physical reality that corresponds to this physical quantity.

Note, the distinction between element of physical reality and physical quantity.

Just because you can predict the value of a physical quantity with certainty, does not mean all such physical quantities which you can predict, must necessarily exist simultaneously. This has been hashed extensively in the "Violation of Bell's inequality" thread.
 
Physics news on Phys.org
  • #72
Another one, with 16 data points:

a, b, c
-----------
+1, +1, -1
-1, -1, +1
+1, +1, -1
-1, -1, +1
+1, +1, -1
+1, +1, -1
-1, -1, +1
+1, +1, -1
+1, +1, -1
+1, +1, -1
-1, -1, +1
+1, +1, -1
+1, +1, -1
+1, +1, -1
-1, -1, +1
+1, +1, -1Just let me know how many points you want. For example here is another 20 point dataset followed by a 30 point one.

a, b, c
-----------
+1, -1, -1
-1, +1, -1
-1, +1, -1
-1, +1, -1
-1, -1, -1
+1, -1, +1
+1, -1, +1
+1, +1, +1
-1, -1, +1
-1, +1, -1
-1, -1, +1
+1, +1, +1
-1, +1, +1
+1, -1, +1
+1, -1, +1
-1, +1, -1
+1, +1, +1
-1, -1, +1
+1, -1, +1
+1, +1, +1 a, b, c
-----------
+1, -1, +1
-1, +1, -1
-1, +1, -1
-1, +1, -1
+1, -1, -1
-1, +1, +1
-1, +1, -1
+1, -1, +1
-1, -1, -1
-1, -1, -1
-1, -1, +1
-1, +1, +1
+1, -1, -1
+1, -1, -1
-1, -1, +1
-1, -1, -1
+1, -1, +1
-1, +1, -1
-1, +1, -1
+1, +1, +1
+1, -1, -1
-1, -1, +1
+1, -1, +1
+1, -1, +1
+1, +1, +1
-1, -1, -1
+1, +1, +1
-1, -1, -1
-1, +1, -1
+1, -1, +1
 
Last edited:
  • #73
billschnieder said:
... In other words, you want a list containing something like (+,-,+) for each identical pair of tablets (photons) corresponding to the *possible outcomes* when mixed with three different liquids (a,b,c) (angles).

Here is the dataset you are requesting. I am providing it despite the fact that you have refused to specify how you will derive terms involving pairs from this dataset to substitute in Bell's inequality 1 + <bc> >= |<ab> - <ac>|, in a manner that is similar to what is done in Bell test experiments.

a, b, c
-----------
-1, +1, -1
+1, -1, -1
+1, +1, -1
-1, -1, -1
-1, -1, -1
-1, +1, +1
-1, +1, -1
+1, +1, -1
+1, +1, -1
+1, -1, -1
+1, -1, +1
+1, -1, +1
-1, +1, +1
+1, +1, +1
-1, +1, -1
+1, +1, +1
+1, +1, +1
-1, +1, -1
-1, -1, -1
-1, -1, +1

OK, great start. The above is for ONE stream of photons. Now according to the EPR entanglement model*, we would be able to predict any ONE of those in advance (use Bob to predict Alice or vice versa). We could also measure any TWO different of ab, bc or ac (one from Alice and a different one from Bob). That would give us more information about Alice than the HUP allows (as EPR argued). Now, my question is: when you run that for any pair of columns I pick, what is your estimate of the match rate? In other words, for the sample you provided: ab has a match rate of 10/20, bc has a rate of 10/20, and ac has a rate of 12/20. I.e. an average of just over 50%.

So in our analogy, I am not asking for any simultaneous triples where we can only measure doubles. So I am not asking for 1 + <bc> >= |<ab> - <ac>| or similar. I am simply asking you: what is your estimate of the coincidence rate for a typical dataset as above? I am guessing that it might be ultimately somewhere between 1/3 and 1/2, would that be fair as an estimate? Keeping in mind, of course, that we are drawing from something constrained as in our analogy.

BTW: my next step will be to ask you to what is the lowest rate of pair coincidences (fewest) you could express in a dataset as above. I.e. if you were trying to minimize coincidences.

* Using Type I PDC entanglement, where you get identical polarization values for Alice and Bob.
 
  • #74
DrChinese said:
OK, great start. The above is for ONE stream of photons. Now according to the EPR entanglement model*, we would be able to predict any ONE of those in advance (use Bob to predict Alice or vice versa).
What are you talking about. You said I should give you only one of the two stream of tablets, which are identical in the above example. So Alice and Bob have exactly the same streams since two tablets are produced at a time. There is no need to predict anything.


We could also measure any TWO different of ab, bc or ac (one from Alice and a different one from Bob).
The above dataset as you requested, consists of the "possible outcomes" of measuring the given tablet(s) using three different liquids (a,b,c). What do you mean now by the statement in bold. This is the reason I wanted this clearly specified upfront so that you don't obfuscate the issue latter as you are now doing. You have the dataset, all that is remaining for you to do is to determine your ab, bc, and ac terms from THAT list and then do your calculation. You asked for the list, I'm assuming you had a reason for asking for the dataset. Now let us see that reason -- do the calculation.

Now, my question is: when you run that for any pair of columns I pick, what is your estimate of the match rate? In other words, for the sample you provided: ab has a match rate of 10/20, bc has a rate of 10/20, and ac has a rate of 12/20. I.e. an average of just over 50%.
What is the match rate supposed to correspond to?

So in our analogy, I am not asking for any simultaneous triples where we can only measure doubles. So I am not asking for 1 + <bc> >= |<ab> - <ac>| or similar. I am simply asking you: what is your estimate of the coincidence rate for a typical dataset as above?
You are confused. Coincidence rate does not come in. Coincidence means the two tablets are measured. For photons, it means the two photons measured, are from the same pair, so that we discount stray photons, and those where only one is measured, in order to ensure that we are measuring a single pair. That does not come into this situation because according to the description you agreed to, both tablets are identical, and I have given you the dataset for one which should be the same as the other, so in a sense the coincidence is 100%. Coincidence does not mean perfect correlation. Even if it meant that, both tablets being identical will still give you a 100% perfect correlation. What's the beef?

I am guessing that it might be ultimately somewhere between 1/3 and 1/2, would that be fair as an estimate?
No. Coincidence does not come into the picture here. You must have something different in mind so spell it out clearly.

BTW: my next step will be to ask you to what is the lowest rate of pair coincidences (fewest) you could express in a dataset as above. I.e. if you were trying to minimize coincidences.
Again, coincidence does not come in here. In real bell test experiments, coincidence is a solution to the problem of imperfect detectors. In this case, we are not losing any tablets.
* Using Type I PDC entanglement, where you get identical polarization values for Alice and Bob.
Again, although I kept insisting on two tablets, you insisted that you wanted just one tablet at a time. I accepted because it does not matter since both tablets are identical anyway so your comment above is moot. You get identical outcome for identical liquids on both tablets.
 
  • #75
billschnieder said:
...You get identical outcome for identical liquids on both tablets.

Sure. Glad we are on the same page. To summarize:

a) You have provided a sample REALISTIC dataset for the 3 liquids (potential angle settings of 0/120/240 degrees, although you may not have yet tweaked them for this specifically). This is for a stream of photons seen by (say) observer Alice.
b) We agree that each individual photon (tab) can be tested with only a single liquid (angle). There are no impossible doubles or triples.
c) We agree that when you prepare a duplicate of Alice's stream, and provide that to Bob, that when Bob checks the same liquids (angles) as Alice, this information is redundant (by definition) because Alice has this. This is following the spirit of the EPR program.

Next steps:

d) We are going to compare when Bob uses a different liquid (angle) to measure than Alice does. Using your example data, my estimate of result matches (Alice with one liquid and Bob with another) is around 1/3 to 1/2. For the specific example you provided, it is just over 1/2 but as I said already, you will get an opportunity to tweak the dataset as you like to obtain a result which is higher or lower. You accept that this is a physically viable experiment and does not involve any impossible triples.

e) Lastly, I will request that you provide a revised dataset - similar to your previous but you can hand pick the values. I would ask that you provide the lowest possible average match rate, again I get to pick the pairings that Alice and Bob will use and will do so without regard to what you provide. All I am asking for is something reasonably low, you don't need to use any special technique.

f) I presume you are intelligent enough to realize that the result of step e) will be a value somewhere around 1/3. But hey, give it your best (or alternately just concede the point and save us both the time). Remember, I have yet to mention any experiment which is not physically feasible. There are no triples, no mixing of possibilities with actualities.

-DrC
 
  • #76
DrChinese said:
Sure. Glad we are on the same page. To summarize:
a) You have provided a sample REALISTIC dataset for the 3 liquids (potential angle settings of 0/120/240 degrees, although you may not have yet tweaked them for this specifically). This is for a stream of photons seen by (say) observer Alice.
b) We agree that each individual photon (tab) can be tested with only a single liquid (angle). There are no impossible doubles or triples.
c) We agree that when you prepare a duplicate of Alice's stream, and provide that to Bob, that when Bob checks the same liquids (angles) as Alice, this information is redundant (by definition) because Alice has this. This is following the spirit of the EPR program.
No we are not on the same page!
a) What I presented is NOT a realistic dataset. It is a dataset of "possiblities". If you still do not understand this point, please review post #49 (https://www.physicsforums.com/showpost.php?p=3335444&postcount=49), and post #186 (https://www.physicsforums.com/showpost.php?p=3333711&postcount=186) in the the "Violation of Bell's theorem" thread.

b) Every tablet can only be tested with one liquid. We have three liquids and two tablets at a time. It is obvious that no experimenter dead or alive could possibly test all three liquids for a given tablet pair. So contrary to your statement, the triple in the dataset is the result of an impossible experiment, even a cave man can understand this. However, you did not ask for the result of an experiment. You asked for a triple of "possibilities" for a given pair for the three liquids. Therefore the triplet (+,-,+) is equivalent to the following three statements together:

(one tablet tested with liquid a, gives bitter taste;
one tablet tested with liquid b, gives sweet taste;
one tablet tested with liquid c, gives bitter taste)

This data point is a triple of possibilities of testing one type of tablet (two of which constitute the the given pair), with the three liquids (a,b,c).

This is not a realistic dataset because the dataset consists of triplets, which can never be simultaneously realized) -- again, because for all three to be realized, we need three tablets but we only have 2.

If you insist to call what I provided you a REALISTIC dataset, it shows that you do not know what realism means and this whole exercise is moot.

Next steps:

d) We are going to compare when Bob uses a different liquid (angle) to measure than Alice does. Using your example data, my estimate of result matches (Alice with one liquid and Bob with another) is around 1/3 to 1/2. For the specific example you provided, it is just over 1/2 but as I said already, you will get an opportunity to tweak the dataset as you like to obtain a result which is higher or lower. You accept that this is a physically viable experiment and does not involve any impossible triples.
The terms ab, bc, and ac are terms corresponding to when Alice and Bob choose a different liquid. Those are the only terms relevant in Bell's inequality which I provided ealier.
* Have you calculated the expectation values for those terms from my list?
* How did you do that? (Please copy the relevant dataset prior to your explanation and results so that I can verify)
* Have you substituted them into Bell's inequality?
* Was it violated or not?


These are the relevant questions you are skirting. Without specifying exactly how you calculated the terms, how am I supposed to know if it corresponds to a possible experiment or not? So unless you clearly explain how you are calculating the terms, I will not agree with what you claim.

e) Lastly, I will request that you provide a revised dataset - similar to your previous but you can hand pick the values. I would ask that you provide the lowest possible average match rate, again I get to pick the pairings that Alice and Bob will use and will do so without regard to what you provide. All I am asking for is something reasonably low, you don't need to use any special technique.

f) I presume you are intelligent enough to realize that the result of step e) will be a value somewhere around 1/3. But hey, give it your best (or alternately just concede the point and save us both the time). Remember, I have yet to mention any experiment which is not physically feasible. There are no triples, no mixing of possibilities with actualities.
One thing at a time. Address the questions above before you start requesting new datasets and predicting what those new datasets might show. The questions above should reveal a lot already about your misunderstanding.

As concerns the part in bold, you haven't presented anything of sufficient detail to enable me to determine that your suggested experiments are physically feasible or not.
 
Last edited by a moderator:
  • #77
billschnieder said:
No we are not on the same page!
...

Arggh! It is my challenge, and we keep going in circles. So let's start again, Mr. Weaver.

- Glass containing Liquid=Angle setting.
- There are 3 types of Liquid used for the test.
- Bottle of Tabs=Stream of Photons
- No idea how many different types of tabs there are, could be 3 or 3000.
- They all look alike, although they are numbered from 1 to N.
- Place a tab in a liquid, you always get Bitter or Sweet.
- Bitter=+1, Sweet=-1.
- You cannot place the same tab in more than one glass. The process destroys the tab completely.

Alice picks tabs out of her bottle. She has a bunch of glasses of liquids, she knows which is which but know nothing about the tabs until she places it in a glass. One tab per glass, and vice versa. Then she tastes the glass and says: Bitter or Sweet! And writes it down.

There is NO second identical bottle of tabs for Bob - yet. We are just trying to create a realistic dataset. Now if you cannot follow this simple example and agree it is realistic a la EPR, I really don't understand how you put your pants on in the morning. EPR says that reality for Alice does NOT depend on Bob. Essentially that means that reality for Alice depends only on Alice (and what is close/local to Alice). Now I am sure that you can map this example to the first dataset of 20 elements and conclude it was in fact a realistic dataset. Because the possible outcomes all exist and are essentially predetermined once Alice starts pulling them out of the bottle in order from 1 to N and testing them in one of the glasses with the liquid of her choosing. But to her, the results seem capriciously random.

So we start with a realistic example. If you can't agree this is a realistic example, then you are essentially ceding my entire argument. Here we have an example where the tabs have simultaneous properties but they cannot be simultaneously tested. The moon exist even when not being observed. So are we in agreement about our example? There are no forbidden triples here.
 
  • #78
billschnieder said:
No we are not on the same page!
a) What I presented is NOT a realistic dataset. It is a dataset of "possiblities".
[..]
Therefore the triplet (+,-,+) is equivalent to the following three statements together:

(one tablet tested with liquid a, gives bitter taste;
one tablet tested with liquid b, gives sweet taste;
one tablet tested with liquid c, gives bitter taste)

This data point is a triple of possibilities of testing one type of tablet (two of which constitute the the given pair), with the three liquids (a,b,c).

This is not a realistic dataset because the dataset consists of triplets, which can never be simultaneously realized) -- again, because for all three to be realized, we need three tablets but we only have 2.

If you insist to call what I provided you a REALISTIC dataset, it shows that you do not know what realism means and this whole exercise is moot.
To me it sounds like a small misunderstanding only: certainly it's a realistic description of conditional observation data. Knowledge of the hidden secrets of this tablet would allow us to tell that IF this tablet would be tested with liquid a, it would yield a bitter taste as data. Correct? That is not experimental output data, but still it is input data for us in this discussion.
The terms ab, bc, and ac are terms corresponding to when Alice and Bob choose a different liquid. Those are the only terms relevant in Bell's inequality which I provided earlier.
[..]
There should also be agreement for the same liquids. However for that requirement your tablets and liquids correspond to the ideal case of 100% correlation.
 
Last edited:
  • #79
billschnieder said:
The terms ab, bc, and ac are terms corresponding to when Alice and Bob choose a different liquid. Those are the only terms relevant in Bell's inequality which I provided ealier.
* Have you calculated the expectation values for those terms from my list?
* How did you do that? (Please copy the relevant dataset prior to your explanation and results so that I can verify)
* Have you substituted them into Bell's inequality?
* Was it violated or not?

I am ignoring the Bell inequality precisely because you don't like the triples. I do not know how to be any more accommodating.
 
  • #80
DrChinese said:
Arggh! It is my challenge, and we keep going in circles. So let's start again, Mr. Weaver.

- Glass containing Liquid=Angle setting.
- There are 3 types of Liquid used for the test.
- Bottle of Tabs=Stream of Photons
- No idea how many different types of tabs there are, could be 3 or 3000.
- They all look alike, although they are numbered from 1 to N.
- Place a tab in a liquid, you always get Bitter or Sweet.
- Bitter=+1, Sweet=-1.
- You cannot place the same tab in more than one glass. The process destroys the tab completely.

Alice picks tabs out of her bottle. She has a bunch of glasses of liquids, she knows which is which but know nothing about the tabs until she places it in a glass. One tab per glass, and vice versa. Then she tastes the glass and says: Bitter or Sweet! And writes it down.

Agreed! This is exactly what I explained.

We are just trying to create a realistic dataset. Now if you cannot follow this simple example and agree it is realistic a la EPR, I really don't understand how you put your pants on in the morning.
We do not yet agree as to what a "realistic dataset" means. This is the point of contention. I have described to you what "realism means" and as a result what "realistic dataset" means. You have done neither. So either you accept my definition and concede that what you request is not a realistic dataset, or provide your own definition of "realism" and your own definition of what "realistic dataset" means. And by providing that you also have to admit that any outcome based on your definitions can not be interpreted to mean my definition is not tenable. This is very simple. You can not use your definition, to draw a conclusion that my definition is not tenable. This the whole point of this exercise.

EPR says that reality for Alice does NOT depend on Bob. Essentially that means that reality for Alice depends only on Alice (and what is close/local to Alice). Now I am sure that you can map this example to the first dataset of 20 elements and conclude it was in fact a realistic dataset.
This is a whole different can of worms we should not be opening here, about what is the difference between ontological dependence and logical dependence. But I agree that nothing Alice does, can have any causal influence over what Bob does according to EPR.

Because the possible outcomes all exist and are essentially predetermined once Alice starts pulling them out of the bottle in order from 1 to N and testing them in one of the glasses with the liquid of her choosing. But to her, the results seem capriciously random.
The bolded statement shows your misunderstanding very clearly. You do not yet understand the difference between something being TRUE and something EXISTING. I have explained this multiple times, in different ways without any statement from you whether you disagree with my explanation, or agree with it. A statement about a conditional possibility is True, but that does not mean the possibility is ACTUALIZED/REALIZED. (See the definition of realized). If you would admit this point, this whole discussion might not be necessary.

So we start with a realistic example. If you can't agree this is a realistic example, then you are essentially ceding my entire argument.
See the above. Just because I point out that you do not understand what is meant by a realistic dataset does not mean I concede your argument. This is at the core of the issue in this thread that we need to reach a consensus on this point in order to proceed. Either you accept my definition and concede that the dataset is not realistic, or you clearly state what you mean by realism and we proceed with your definition with the understanding that any future conclusion will be limited to your definition. The ball is in your court.

Here we have an example where the tabs have simultaneous properties but they cannot be simultaneously tested. The moon exist even when not being observed. So are we in agreement about our example?
Yes. Agreed. According to my definition of realism, a dataset containing triplets of these simultaneousl properties will be a realistic dataset.

There are no forbidden triples here.
But you just said they could not be simultaneously tested. That is an admission that something is impossible. Testing produces outcomes, that is why according to my definition of realism, if all the outcomes in the triplet can not all be simultaneously tested, it is not a realistic dataset according to my definition.
 
  • #81
harrylin said:
To me it sounds like a small misunderstanding only
I disagree. It is the central issue -- what does realism mean.

certainly it's a realistic description of conditional observation data
Phrased like that, it seems like it might make sense. But let us expand it and to (if a then +, if b then -, if c then +), you see then that If a, and if b, then definitely not c, which means
(if a then +, if b then -, if c then +) =/= (+,-,+)

In the LHS the possibilities are all simultaneously True, but that does not mean the outcomes in the RHS are simultaneously real. They can never be.

Knowledge of the hidden secrets of this tablet would allow us to tell that IF this tablet would be tested with liquid a, it would yield a bitter taste as data. Correct?
Correct.

That is not experimental output data, but still it is input data for us in this discussion.
It is input data for the discussion, that is why I provided the dataset. However, the next part now is to discuss how this is compatible with any experiment that could ever be performed.

There should also be agreement for the same liquids. However for that requirement your tablets and liquids correspond to the ideal case of 100% correlation.
It is a moot point since we already agreed that Bob and Alice could get the exact same tablet type which corresponds to 100%. The reason I say it is not relevant is because Bell's inequality does not contain "aa", "bb", "cc" terms.
 
  • #82
DrC.
So I'm waiting for your answers to these questions

1 + <bc> >= |<ab> - <ac>|

* Have you calculated the expectation values for those terms from any of the dataset I presented?
* How did you do that? (Please copy the relevant dataset prior to your explanation and results so that I can verify)
* Have you substituted them into Bell's inequality?
* Was it violated or not?

I am explicitly asking you these questions, you can't simply ignore them. They are relevant.
 
  • #83
billschnieder said:
DrC.
So I'm waiting for your answers to these questions

1 + <bc> >= |<ab> - <ac>|

* Have you calculated the expectation values for those terms from any of the dataset I presented?
* How did you do that? (Please copy the relevant dataset prior to your explanation and results so that I can verify)
* Have you substituted them into Bell's inequality?
* Was it violated or not?

I am explicitly asking you these questions, you can't simply ignore them. They are relevant.

No, because you don't like that. So no need to do that.
 
  • #84
DrChinese said:
No, because you don't like that. So no need to do that.

Who is bobbing and weaving now. I ask you a question and you refuse to answer because according to you, I do not like the question? Huh?

For those following, note that DrC has refused to answer the question twice and he knows why. It is because he has calculated it and realized that based on how you calculate <ab>, <bc> and <ac>, the inequality can be violated. If you calculate it in a way consistent with Bell test experiments, the inequality is violated. If you calculate it the way Bell intended, the inequality is satisfied but the corresponding experiment is impossible as it will require measuring tablets more than once. This is the real reason DrC does not want to answer the question.

Again, it doesn't make sense to say I do not like the question I asked. I'm asking it which means I like the question. If there was any doubt that I did not like the question, I am declaring in the open that I do like the questions I asked and here they are again:

First one of the datasets (you can pick anyone you like other than this one):

a, b, c
-----------
+1, -1, +1
-1, +1, -1
-1, +1, -1
-1, +1, -1
+1, -1, -1
-1, +1, +1
-1, +1, -1
+1, -1, +1
-1, -1, -1
-1, -1, -1
-1, -1, +1
-1, +1, +1
+1, -1, -1
+1, -1, -1
-1, -1, +1
-1, -1, -1
+1, -1, +1
-1, +1, -1
-1, +1, -1
+1, +1, +1
+1, -1, -1
-1, -1, +1
+1, -1, +1
+1, -1, +1
+1, +1, +1
-1, -1, -1
+1, +1, +1
-1, -1, -1
-1, +1, -1
+1, -1, +1

Then Bell's inequality:
1 + <bc> >= |<ab> - <ac>|

Then the relevant questions for DrC, which I like very much:

* Have you calculated the expectation values for those terms from any of the datasets I presented?
* How did you do that? (Please copy the relevant dataset prior to your explanation and results so that I can verify)
* Have you substituted them into Bell's inequality?
* Was it violated or not?
 
Last edited:
  • #85
billschnieder said:
...Again, it doesn't make sense to say I do not like the question I asked. I'm asking it which means I like the question. If there was any doubt that I did not like the question, I am declaring in the open that I do like the questions I asked and here they are again:

First one of the datasets (you can pick anyone you like other than this one):

a, b, c
-----------
+1, -1, +1
-1, +1, -1
-1, +1, -1
-1, +1, -1
+1, -1, -1
-1, +1, +1
-1, +1, -1
+1, -1, +1
-1, -1, -1
-1, -1, -1
-1, -1, +1
-1, +1, +1
+1, -1, -1
+1, -1, -1
-1, -1, +1
-1, -1, -1
+1, -1, +1
-1, +1, -1
-1, +1, -1
+1, +1, +1
+1, -1, -1
-1, -1, +1
+1, -1, +1
+1, -1, +1
+1, +1, +1
-1, -1, -1
+1, +1, +1
-1, -1, -1
-1, +1, -1
+1, -1, +1

Then Bell's inequality:
1 + <bc> >= |<ab> - <ac>|

Then the relevant questions for DrC, which I like very much:

1. Have you calculated the expectation values for those terms from any of the datasets I presented?
2. How did you do that? (Please copy the relevant dataset prior to your explanation and results so that I can verify)
3. Have you substituted them into Bell's inequality?
4. Was it violated or not?

Let's see: you were in the act of accepting my challenge (bob, weave) and now you have issued the billschnieder challenge. I don't get it, but it seems easy enough.

1. Yes
2. I used the entire universe of the following which you provided, it is the first 10 rows.

+1, -1, +1
-1, +1, -1
-1, +1, -1
-1, +1, -1
+1, -1, -1
-1, +1, +1
-1, +1, -1
+1, -1, +1
-1, -1, -1
-1, -1, -1

ab=.2 (2/10)
bc=.4 (4/10)
ac=.8 (8/10)

3. Yes, the result is:

1+.4>=| .2 - .8 |
1.4 >= .6

4. No.

Care to repeat this (futile) exercise again? Or why don't you just give me your answer? Because I am going to tell you that Bell's Inequality is not going to be violated. You can try to manipulate things, but the issue is whether the realistic condition - that out of 8 permutations (+++, ++-, etc.), all have a likelihood of 0 to 1. And they will, in any realistic dataset, by definition.
 
Last edited:
  • #86
DrChinese said:
[..]
1. Yes
2. I used the entire universe of the following which you provided, it is the first 10 rows.

+1, -1, +1
-1, +1, -1
-1, +1, -1
-1, +1, -1
+1, -1, -1
-1, +1, +1
-1, +1, -1
+1, -1, +1
-1, -1, -1
-1, -1, -1

ab=.2 (2/10)
bc=.4 (4/10)
ac=.8 (8/10)

3. Yes, the result is:

1+.4>=| .2 - .8 |
1.4 >= .6

4. No.

[..].

That is strange... DrC, I don't understand how you got those numbers. How could you use a data set of 10 rows for sets of 3 liquids? I can only use the data in multiples of 3. This is what I get with your selection (omitting the last row), arbitrarily sampling in the sequence that the combinations appear in the inequality:

a b c
+1, -1, +1 -> bc1= -1
-1, +1, -1 -> ab1= -1
-1, +1, -1 -> ac1= -1
-1, +1, -1 -> bc2= -1
+1, -1, -1 -> ab2= 1
-1, +1, +1 -> ac2= 1
-1, +1, -1 -> bc3= -1
+1, -1, +1 -> ab3= -1
-1, -1, -1 -> ac3= 1

<bc> = SUM(bc)/N = (-1 + -1 + -1) = -3/3
<ab> = SUM(ab)/N = (-1 + 1 + -1) = -2/3
<ac> = SUM(ac)/N = (-1 + 1 + 1) = 1/3

1 + <bc> >=? |<ab> - <ac>|
1 + -1 >=? |-2/3 - 1/3|
0 >=? +1

That is invalid; thus I get for this example that the inequality is violated.
Did I do something wrong?

Thanks,
Harald
 
  • #87
harrylin said:
That is strange... DrC, I don't understand how you got those numbers. How could you use a data set of 10 rows for sets of 3 liquids? I can only use the data in multiples of 3. This is what I get with your selection (omitting the last row), arbitrarily sampling in the sequence that the combinations appear in the inequality:

a b c
+1, -1, +1 -> bc1= -1
-1, +1, -1 -> ab1= -1
-1, +1, -1 -> ac1= -1
-1, +1, -1 -> bc2= -1
+1, -1, -1 -> ab2= 1
-1, +1, +1 -> ac2= 1
-1, +1, -1 -> bc3= -1
+1, -1, +1 -> ab3= -1
-1, -1, -1 -> ac3= 1

<bc> = SUM(bc)/N = (-1 + -1 + -1) = -3/3
<ab> = SUM(ab)/N = (-1 + 1 + -1) = -2/3
<ac> = SUM(ac)/N = (-1 + 1 + 1) = 1/3

1 + <bc> >=? |<ab> - <ac>|
1 + -1 >=? |-2/3 - 1/3|
0 >=? +1

That is invalid; thus I get for this example that the inequality is violated.
Did I do something wrong?

Thanks,
Harald

We are drifting off into the ozone, because we have made the method of calculation for one of bill's assertions our focus - and it shouldn't be. The reason I always set up the examples myself is to prevent situations like this where we argue pointlessly over the assignment of values. In my calculation, I took the matches to be 1 and mismatches to be 0. So ++ or -- is 1, +- or -+ is 0. I don't really care for bill's form of Bell's Inequality, though to be fair it is the original from Bell. And the reason is precisely this, because it entirely obscures the point. Which is that the assertion of realism imposes a burden on a theory which, when expressed mathematically, cannot be met by one which is also local. So I am simply asking any realist to present their version of a mathematical requirement associated with realism.

My goal had been to address his point that Bell tests don't make sense because they involve "impossible" experiments. I was going to do that by showing that if you start with a realistic dataset, you cannot get agreement with QM in possible experiments. That was Bell's essential point.

If you deny that observables corresponding to particle properties (EPR's "elements of reality") have definite values at all times: that IS the mainstream view and it is labeled by the scientific community as "non-realism". But you can call it Al or anything you want.
 
  • #88
I think you will find this a better expression of Bell's idea for this case:

Matches(ab) + Mismatches(ac) - Matches(bc) >= 0

Doesn't matter what you label as a, b or c. Using the first 10 data points bill provided:

a b c
+1, -1, +1
-1, +1, -1
-1, +1, -1
-1, +1, -1
+1, -1, -1
-1, +1, +1
-1, +1, -1
+1, -1, +1
-1, -1, -1
-1, -1, -1

ab matches=2
ac mismatches=2
bc matches=4

2+2-4 >= 0

Try it on a few datasets and you should quickly agree that it works for all.
 
  • #89
In fact, use just 1 datapoint and make it anything you like:

a b c
+ - +
or
? ? ?

Matches(ab) + Mismatches(ac) - Matches(bc) >= 0

0 + 1 - 1 >= 0

or

? + ? - ? >= 0

Obviously, if it works for the single case you hand pick to violate it, it works also for all cases.
 
  • #90
DrChinese said:
We are drifting off into the ozone, because we have made the method of calculation for one of bill's assertions our focus - and it shouldn't be.
I don't think so: we test here a realistic illustration of Bell's Theorem with Bell's method of calculation that corresponds to his theorem as he originally wrote it. Just as easy as Bertlmann's socks, but better matching the photon and electron experiments.
The reason I always set up the examples myself is to prevent situations like this where we argue pointlessly over the assignment of values. In my calculation, I took the matches to be 1 and mismatches to be 0. So ++ or -- is 1, +- or -+ is 0. I don't really care for bill's form of Bell's Inequality, though to be fair it is the original from Bell. And the reason is precisely this, because it entirely obscures the point. [...]
OK that is indeed a minor problem, I had forgotten about the two conventions. Thanks for pinpointing that issue!
In the paper on which this discussion is based, De Raedt writes:
It is often convenient to work with variables S = ±1 instead of x = 0, 1

As far as I can see, from thereon he uses S throughout his paper, and not x. So, in order to avoid confusion, please stick in this thread to that calculation convention which Bell also used in his original paper.

Anyway, perhaps due to the distraction by that minor issue, you did not notice the main issue which I brought up, and which probably relates to what Bill intended to show - indeed it's even the main point, I think, of De Raedt's paper:
How could you use a data set of 10 rows for tests with 3 liquids? I can only use the data in multiples of 3, in the way I showed. One row corresponds to the hidden possible experience of one tablet as well of its double (just like a pair of Bertlmann's socks). Thus only two experiences (with two liquids) are possible per row of data. Bell elaborates about that same issue in "Bertlmann's socks" (there it concerns two new socks that cannot be tested for three temperatures).

PS in a follow-up post you write:
In fact, use just 1 datapoint and make it anything you like [...]
Obviously, if it works for the single case [...]
In this example, a single input data point such as [a,b,c] = [+ + -] corresponds to the hidden possible experiences of one pair of tablets with the three liquids a, b and c. If you insist on only one tablet, then you reduce it to only one tablet that dissolves in one liquid. It is impossible to test with one or two tablets a prediction concerning tests of dissolving whole tablets in three different liquids!
 
Last edited:
  • #91
harrylin said:
Anyway, perhaps because you were distracted by that minor issue, you did not notice the main issue which I brought up, an issue that probably relates to what Bill intended to show: How could you use a data set of 10 rows for tests with 3 liquids? I can only use the data in multiples of 3, in the way I showed. One row corresponds to the hidden possible experience of one tablet as well of its double (just like a pair of Bertlmann's socks). Thus only two experiences (with two liquids) are possible per row of data.

No problem, we can do that too. We will just draw randomly 2 from each triple. The issue there is that you need a sufficient sample size (a small one can potentially give results that do violate the inequality).

a, b, c
-----------
take ab from these
+1, -1, +1
-1, +1, -1
-1, +1, -1
-1, +1, -1
+1, -1, -1
-1, +1, +1
-1, +1, -1
+1, -1, +1
-1, -1, -1
-1, -1, -1
2 matches, 8 mismatches, your value is (2-8)/10 or -.6

take ac from these
-1, -1, +1
-1, +1, +1
+1, -1, -1
+1, -1, -1
-1, -1, +1
-1, -1, -1
+1, -1, +1
-1, +1, -1
-1, +1, -1
+1, +1, +1
5 matches, 5 mismatches, your value is (5-5)/10 or 0

take bc from these
+1, -1, -1
-1, -1, +1
+1, -1, +1
+1, -1, +1
+1, +1, +1
-1, -1, -1
+1, +1, +1
-1, -1, -1
-1, +1, -1
+1, -1, +1
5 matches, 5 mismatches, your value is (5-5)/10 or 0

So by my formula:

Matches(ab) + Mismatches(ac) - Matches(bc) >= 0
2+5-5 >= 0
Respected.

By bill's using your +/- notation (don't recall if that is correct or not):

1 + <bc> >= |<ab> - <ac>|

1+ 0 >= |-.6 - 0|
Respected.

This is a pointless exercise, as you will eventual realize, because it gives a result in accordance with realism precisely because it is realistic. Only if a sufficiently small or intentionally biased sample is presented will it be violated. No matter how you try, you won't make it work unless there is a conspiracy between the dataset values and the selection of when you get ab, ac or bc.

But none of this is the basis for my argument anyway. My argument goes in a different direction.
 
Last edited:
  • #92
DrChinese said:
2. I used the entire universe of the following which you provided, it is the first 10 rows.

+1, -1, +1
-1, +1, -1
-1, +1, -1
-1, +1, -1
+1, -1, -1
-1, +1, +1
-1, +1, -1
+1, -1, +1
-1, -1, -1
-1, -1, -1
This is crap. Full-universe by what definition. What made you think the dataset I gave you is not the full universe? This is just further obfuscation, bobbing and weaving by you! You have not justified, nor can justify why you picked just those 10 values out of the 30 I gave you, other than an attempt to maybe rig the results. But this is not going to work and the more you pull such silly stunts the more you end up undoing yourself.

ab=.2 (2/10)
bc=.4 (4/10)
ac=.8 (8/10)
As harrylin has pointed out already, your convention is mixed up. Further obfuscation, bobbing and weaving again, instead of just sticking to the program we already agreed to? Common DrC, let us be intellectually honest adults here!

I can see that conventions put aside, you are using every triple to calculate <bc>, using every triple to calculate <ac> and doing the exact same thing for <ab>. It is clear by now to anyone following this thread that this can not be done in a feasible experiment. Remember what I said?

based on how you calculate <ab>, <bc> and <ac>, the inequality can be violated. If you calculate it in a way consistent with Bell test experiments, the inequality is violated. If you calculate it the way Bell intended, the inequality is satisfied but the corresponding experiment is impossible as it will require measuring tablets more than once.

3. Yes, the result is:

1+.4>=| .2 - .8 |
1.4 >= .6
Using the standard convention which Bell used, and we agreed to, where P(a,b) stands for the expectation value of the paired-product of outcomes at Alice and Bob where liquids (a,b) were tested respectively, I get the following values for the terms:

1) As Bell intended -- ie using every tablet in the dataset to calculate every term
ab = -0.266666666667
bc = -0.266666666667
ac = 0.2

Plug them into 1 + <bc> >= |<ab> - <ac>|
and get 1 - 0.267 >= | 0.267 -0.2 | (Inequality RESPECTED, but notice that the corresponding experiment, measuring two tablets in three liquids, is impossible to perform)

2) Similar to Bell test experiments with 3-runs with fixed settings. Firs run measures 10 pairs of tablets using liquids (a,b) to calculate <a1b1>, second run using liquids (b,c) for next 10 pairs of tablets to calculate <b2c2>, third run using liquids (a,c) for the remaining 10 pairs to calculate <a3c3>.

a1b1 =-0.4
b2c2 =-0.4
a3c3 = 0.4

Substitute in, 1 + <bc> >= |<ab> - <ac>|, to get 1 - 0.4 >= |-0.4-0.4|
0.6 >= 0.8 (Inequality VIOLATED, note however that as I have explained previously, the reason we get the violation is because the inequality expects expectation values of the type mentioned in (1), note also that in the De Raedt paper which started this thread, they have shown that starting with a expectation values of the type (2), Bell's inequality can not be derived, instead a different inequality is derived which is not violated by any experiments.)3) Similar to Bell test experiments with random switching. Tablet pairs are randomly chosen from the 30 pairs (WITHOUT REPLACEMENT!). First 10 random pairs of tablets are tested using liquids (a,b) to calculate <a1b1>, second run using liquids (b,c) to calculate <b2c2>, and the remaining 10 using (a,c) to calculate <a3c3>.

a1b1 =-0.6
b2c2 =-0.2
a3c3 = 0.4

Substitute in, 1 + <bc> >= |<ab> - <ac>|, to get 1 - 0.2 >= |-0.6-0.4|
0.8 >= 1 (Inequality VIOLATED for the same reason as explained in (2))

You can try to manipulate things, but the issue is whether the realistic condition - that out of 8 permutations (+++, ++-, etc.), all have a likelihood of 0 to 1. And they will, in any realistic dataset, by definition.
Huh? Who is talking about permutations. More obfuscation I see. Permutations don't come in at all, that is if you understand what is going on. Likelihood does not come in at all. Each term in Bell's inequality is an expectation value for the paired product of the outcomes!

You take each Alice's outcome, multiply with Bob's add them all up, for EVERY photon pair, and then take the average. That is what <ab> means. Bell defined this clearly at the very beginning of his original paper.
 
  • #93
DrChinese said:
No problem, we can do that too. We will just draw randomly 2 from each triple.
Now tell us clearly, did you randomly pick the two with or without replacement? In other words, did you use any of the triplets more than once? This is the crucial question you still refuse to answer.


The issue there is that you need a sufficient sample size (a small one can potentially give results that do violate the inequality).
Now you are contradicting yourself. Is it not you who said: Obviously, if it works for the single case you hand pick to violate it, it works also for all cases.


Besides, I already asked you to specify any number and I will generate the dataset containing that number of entries.

a, b, c
-----------
take ab from these
+1, -1, +1
-1, +1, -1
-1, +1, -1
-1, +1, -1
+1, -1, -1
-1, +1, +1
-1, +1, -1
+1, -1, +1
-1, -1, -1
-1, -1, -1
2 matches, 8 mismatches, your value is (2-8)/10 or -.6

take ac from these
-1, -1, +1
-1, +1, +1
+1, -1, -1
+1, -1, -1
-1, -1, +1
-1, -1, -1
+1, -1, +1
-1, +1, -1
-1, +1, -1
+1, +1, +1
5 matches, 5 mismatches, your value is (5-5)/10 or 0

take bc from these
+1, -1, -1
-1, -1, +1
+1, -1, +1
+1, -1, +1
+1, +1, +1
-1, -1, -1
+1, +1, +1
-1, -1, -1
-1, +1, -1
+1, -1, +1
5 matches, 5 mismatches, your value is (5-5)/10 or 0

So by my formula:

Matches(ab) + Mismatches(ac) - Matches(bc) >= 0
2+5-5 >= 0
Respected.

By bill's using your +/- notation (don't recall if that is correct or not):

1 + <bc> >= |<ab> - <ac>|

1+ 0 >= |-.6 - 0|
Respected.
Again, did you use any of the triplets in more than one group? If you did, then you haven't done anything different from what I explained in my previous post under Treatment (1) -- ie the one corresponding to the impossible experiment. Sure Bell's inequality will be respected in that Treatment, but so what, it doesn't mean squat as it is not equivalent to any performable experiment. My Treatments (2) and (3) are consistent with how Bell test experiments are performed but they violate the inequality.

Which goes to show that violation of Bell's inequality by actual experiments has no ramifications for "realism", or "locality" or "CFD" or anything. It simply points to the fact that the terms from experiment and QM are not the type of terms implicitly required by the inequalities.

What was the point of your challenge again? I hope the next time you think of proclaiming that "realism" or "locality" or "CFD" is untenable, you will think about this exchange.
 
  • #94
I find this example very useful, thanks. :smile:
billschnieder said:
[..]
1) As Bell intended -- ie using every tablet in the dataset to calculate every term
[...]
I don't think so: Bell clearly explained in his "Bertlmann's socks"* talk that it is simply impossible to use the dataset of one pair of socks to calculate all three terms of the inequality. That is now also clearly explained in this thread.

As I mentioned in post #64, the issue here is the averaging of results from different pairs for Bell's inequality, which Bell argued to be valid while de Raedt argues this to be invalid.

Harald

*http://cdsweb.cern.ch/record/142461?ln=en
 
  • #95
billschnieder said:
Now tell us clearly, did you randomly pick the two with or without replacement? In other words, did you use any of the triplets more than once? This is the crucial question you still refuse to answer. ...

Again, did you use any of the triplets in more than one group? If you did, then you haven't done anything different from what I explained in my previous post under Treatment (1) -- ie the one corresponding to the impossible experiment. Sure Bell's inequality will be respected in that Treatment, but so what, it doesn't mean squat as it is not equivalent to any performable experiment. My Treatments (2) and (3) are consistent with how Bell test experiments are performed but they violate the inequality.

Which goes to show that violation of Bell's inequality by actual experiments has no ramifications for "realism", or "locality" or "CFD" or anything...

I answered already that I used your 30 items. I answered that I used them without replacement. I answered already that this entire exercise is a waste of time.

You pretended to take my challenge but then stopped. I told you that you don't need the usual Bell inequality if you start with a realistic dataset. Well, we have both agreed now that since no realistic datasets are possible, that the usual definition (not yours mind you) of realism fails.

Given that you a) are a crabby fellow; b) are given to an excess of drama over what should be some friendly sparring; and worst of all c) cannot even spell your name correctly (and I should know): I have decided not to continue this discussion. You will, I am quite certain, proclaim the brilliance of your "victory" for your fringe viewpoints.

But don't expect me not to reply to your usual wrong statements as always. After all, I remain DrC. :biggrin:
 
  • #96
harrylin said:
As I mentioned in post #64, the issue here is the averaging of results from different pairs for Bell's inequality, which Bell argued to be valid while de Raedt argues this to be invalid.

Harald

*http://cdsweb.cern.ch/record/142461?ln=en

As mentioned, if you are a realist: where is a realistic dataset? De Raedt provided one (actually a simulation formula, but I used it to create a successful dataset), and his is the only team that has accepted this challenge. Keep in mind that it makes predictions different than QM, which is the entire point of Bell if anyone here is still listening.
 
  • #97
billschnieder;3346881 said:
[...]
3) Similar to Bell test experiments with random switching. Tablet pairs are randomly chosen from the 30 pairs (WITHOUT REPLACEMENT!). First 10 random pairs of tablets are tested using liquids (a,b) to calculate <a1b1>, second run using liquids (b,c) to calculate <b2c2>, and the remaining 10 using (a,c) to calculate <a3c3>.

a1b1 =-0.6
b2c2 =-0.2
a3c3 = 0.4

Substitute in, 1 + <bc> >= |<ab> - <ac>|, to get 1 - 0.2 >= |-0.6-0.4|
0.8 >= 1 (Inequality VIOLATED for the same reason as explained in (2)) [..]

Now this is an important point; and Bill, I must admit that I did not expect such an outcome when you started this simple example!

Even when I did the exercise for the first 9 data points I thought that if I did not make an error, it may still be just coincidence. But if a high amount of random input data indeed breaks Bell's inequality for this type of test, then you managed to provide just the kind of illustration that De Raedt's paper lacks and for which I made a wishful request in post #46.

When I find the time I'll also try your example for more random inputs. :smile:
 
Last edited:
  • #98
harrylin said:
...When I find the time I'll also try your example for more random inputs. :smile:

Bill is WRONG, as usual. If the data is realistic, this will not happen with anything other than a rigged sample. But hey, good luck with that! Usually, this exercise should serve to help you understand WHY Bill's assertions are incorrect. Just remember to keep in mind what the inequality is. I explain this at my site:

Bell's Theorem and Negative Probabilities

If you follow this derivation of Bell, you cannot go wrong.



----Table from the page showing realism requirement, 8 permutations----

Case --Outcomes-- Predicted likelihood of occurance
[1] A+ B+ C+ >=0
[2] A+ B+ C- >=0
[3] A+ B- C+ >=0
[4] A+ B- C- >=0
[5] A- B+ C+ >=0
[6] A- B+ C- >=0
[7] A- B- C+ >=0
[8] A- B- C- >=0
Where: A=0 degrees B=67.5 degrees C=45 degrees
 
  • #99
DrChinese said:
[..] where is a realistic dataset? Keep in mind that it makes predictions different than QM, which is the entire point of Bell if anyone here is still listening.

Hmmm... if that was "the entire point", then few people would be bothered by Bell's Theorem. :-p
Perhaps we should remind ourselves of Bell's entire point, which De Raedt challenges:
In a theory in which parameters are added to quantum mechanics to determine the results of individual measurements, without changing the statistical predictions, there must be a mechanism whereby the setting of one measuring device can [instantaneously] influence the reading of another instrument, however remote.
- On the EPR paradox

and even:
So the quantum correlations are locally inexplicable
- Bertlmann's socks

Thus Bell claimed to have proved a very weird fact that can never be explained by a "local" theory so that it needs to be explained by for example "spooky action at a distance".

Such a claim (theorem) can be invalidated in two ways:

1. By providing a counter example that the theorem claims to be impossible.
2. By showing that the theorem is based on at least one invalid assumption.

The topic of this thread is about De Raedt's attempt at way no.2, and not about way no.1.
 
  • #100
harrylin said:
Hmmm... if that was "the entire point", then few people would be bothered by Bell's Theorem. :-p

"In a theory in which parameters are added to quantum mechanics to determine the results of individual measurements, without changing the statistical predictions,..."

Good quote. And it means that IF the Inequality is respected, then the results do not agree with QM's predictions. People forget this critical point. Start with a realistic dataset and you won't end up with predictions that match the QM expectation for some angles. All the stuff about Bell Inequalities - how folks attempt to dissect them - does not change this fact. I have given you all the tools to understand this. But you are biased by the end result you want to achieve.

You can derive Bell yourself from scratch. I did, so it can't be THAT hard. Go through the logic from one of my pages and you will see that there are no weird assumptions needed. You start from ANY reasonable realistic requirement, use the Bell thought process knowing a few good angles to use, and voila.

So you want to supply the added parameters mentioned in the quote above. You will see quickly that the MALUS cos^2 relationship goes out the window. For ONE photon stream, not TWO. (That is precisely what happened to the De Raedt team, by the way, as they quite properly pointed out before I got started with their simulation.)
 
  • #101
DrChinese said:
"In a theory in which parameters are added to quantum mechanics to determine the results of individual measurements, without changing the statistical predictions,..."

Good quote. And it means that IF the Inequality is respected, then the results do not agree with QM's predictions. People forget this critical point. Start with a realistic dataset [...]
That means regretfully that you did not read or understand the next part of my reply:

"Such a claim (theorem) can be invalidated in two ways:

1. By providing a counter example that the theorem claims to be impossible.
2. By showing that the theorem is based on at least one invalid assumption.

The topic of this thread is about De Raedt's attempt at way no.2, and not about way no.1."
So you want to supply the added parameters mentioned in the quote above. [...]
No, why do you think that I have that ambition? As before you confuse me with someone else. However, De Raedt does have that ambition and as you know that is the topic of another thread, which you started:
https://www.physicsforums.com/showthread.php?t=369286
 
Last edited:
  • #102
harrylin said:
That means regretfully that you did not read or understand the next part of my reply... ... showing that the theorem is based on at least one invalid assumption...

You're funny. :biggrin: It really is humorous when folks believe they have found, in a few hours, the one thing that thousands of professional physicists have missed after years of study of this very subject. I would say that most of these professionals have a pretty strong understanding of the Bell assumptions. That is precisely why Bell is so well regarded. You might try reading a few hundred mainstream papers and see if that widens your perception any.

But hey, you are welcome to believe anything you want. Perhaps you believe in flying dogs too... here is a picture that "proves" it:

FlyingDog.jpg
 
  • #103
Just to be clear: If you are here to learn how/why Bell's Theorem works, you are at the right place. If you are here to tear down Bell, you are at the WRONG place. Bell is generally accepted science.

It is not incumbent on folks here to "prove" that the de Raedt team's latest paper is not applicable to Bell. If someone cares to ask why a certain particular element of their reasoning is invalid, I'm sure there will be discussion around that. But if you can't express their reasoning yourself, I don't plan to do your analysis for you.
 
  • #104
DrChinese said:
You're funny. :biggrin: It really is humorous when folks believe they have found, in a few hours, the one thing that thousands of professional physicists have missed after years of study of this very subject.
Yes indeed - for any onlookers: Dr.C misquoted me, making it appear nearly the contrary of what I wrote. :biggrin:
OK then I'll do the same here:
...flying dogs... here is a picture that proves it:
FlyingDog.jpg
It's really humorous that you also believe in flying dogs. :wink:

PS in case you really misunderstood what I wrote, see:
https://www.physicsforums.com/showthread.php?t=123652
 
Last edited:
  • #105
DrChinese said:
Just to be clear: [...] It is not incumbent on folks here to "prove" that the de Raedt team's latest paper is not applicable to Bell. [..]
It depends on what you mean with "here": this thread is not about how Bell's Theorem works nor about an attempt to construct a realistic model. in this thread we discuss the arguments of De Raedt's latest paper about Boole-Bell. Do you want me to follow your example and start discussing Boolean logic in the thread on De Raedt's latest computer simulations?
 

Similar threads

Replies
0
Views
675
Replies
50
Views
4K
  • Quantum Interpretations and Foundations
10
Replies
333
Views
11K
  • Quantum Interpretations and Foundations
Replies
2
Views
792
Replies
25
Views
2K
Replies
6
Views
2K
  • Quantum Physics
Replies
7
Views
1K
Replies
4
Views
1K
  • Quantum Physics
3
Replies
82
Views
10K
Replies
75
Views
8K
Back
Top