MHB Boundary conditions spherical coordinates

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The discussion focuses on solving Laplace's equation in spherical coordinates with specified boundary conditions, where the solution is expressed as a series involving Legendre polynomials. The boundary conditions are defined as u(a, θ) = f(θ) and u(b, θ) = 0, leading to a general solution that includes terms with coefficients A_n and B_n. The goal is to transform the general solution into a specific form that incorporates the boundary conditions, but difficulties arise in achieving this transformation. The relationship involving the coefficients A_n and the integral of f(θ) is crucial for the solution. Ultimately, the problem has been resolved by the participant.
Dustinsfl
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Laplace axisymmetric
$u(a,\theta) = f(\theta)$ and $u(b,\theta) = 0$ where $a<\theta<b$.

The general soln is
$$
u(r,\theta) = \sum_{n=0}^{\infty}A_n r^n P_n(\cos\theta) + B_n\frac{1}{r^{n+1}}P_n(\cos\theta)
$$

I am supposed to obtain
$$
u(r,\theta) = \sum_{n = 0}^{\infty}A_n\left[\left(\frac{r}{b}\right)^n - \frac{b}{r}^{n + 1}\right]P_n(\cos\theta)
$$
with
$$
A_nb^n\left[\left(\frac{r}{b}\right)^n - \frac{b}{r}^{n + 1}\right] = \frac{2n + 1}{2}\int_0^{\pi}f(\theta)P_n(\cos\theta) \sin \theta d\theta.
$$
Using the BC I can't obtain that.
 
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dwsmith said:
Laplace axisymmetric
$u(a,\theta) = f(\theta)$ and $u(b,\theta) = 0$ where $a<\theta<b$.

The general soln is
$$
u(r,\theta) = \sum_{n=0}^{\infty}A_n r^n P_n(\cos\theta) + B_n\frac{1}{r^{n+1}}P_n(\cos\theta)
$$

I am supposed to obtain
$$
u(r,\theta) = \sum_{n = 0}^{\infty}A_n\left[\left(\frac{r}{b}\right)^n - \frac{b}{r}^{n + 1}\right]P_n(\cos\theta)
$$
with
$$
A_nb^n\left[\left(\frac{r}{b}\right)^n - \frac{b}{r}^{n + 1}\right] = \frac{2n + 1}{2}\int_0^{\pi}f(\theta)P_n(\cos\theta) \sin \theta d\theta.
$$
Using the BC I can't obtain that.

I have this solved.
 

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