Bouyency and Water Discplacement of 2 Fluids

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SUMMARY

The discussion centers on calculating the difference in volume between fresh water and salt water displaced by a boat floating in fresh water, with a buoyant force of 37.3 kN. The formula used is V(f) - V(s) = [F(bu)/(rho)][1/(rho_f) - 1/(rho_s)], where rho_f is the density of fresh water (0.998E3 kg/m^3) and rho_s is the density of salt water (1.10E3 kg/m^3). The calculated difference in volume is 0.354 m³, which some participants believe to be incorrect, despite the calculations appearing accurate.

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Homework Statement



A boat floating in fresh water displaces water weighing 37.3 kN. What is the difference between the volume of fresh water displaced and the volume of salt water displaced (Vfresh - Vsalt)?

F(bu) = 37.3E3 kg/m^3
(rho)fresh water = .998E3 kg/m^3?
(rho)salt water = 1.10E3 kg/m^3?


Homework Equations



F(bu) = m(of water displaced)g
m(of water displaced) = (rho)V


The Attempt at a Solution



F(bu) = (rho)Vg
V = F(bu)/[(rho)g]
V(f) - V(s) = [F(bu)/(rho)][1/(rhof)-1/(rhos)]
V(f) - V(s) = [37.3E3/9.8][1/(.998E3) - 1/(1.10E3)] = .354m^3

This is wrong?
 
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vMaster0fPuppet said:

Homework Statement



A boat floating in fresh water displaces water weighing 37.3 kN. What is the difference between the volume of fresh water displaced and the volume of salt water displaced (Vfresh - Vsalt)?

F(bu) = 37.3E3 kg/m^3
(rho)fresh water = .998E3 kg/m^3?
(rho)salt water = 1.10E3 kg/m^3?


Homework Equations



F(bu) = m(of water displaced)g
m(of water displaced) = (rho)V


The Attempt at a Solution



F(bu) = (rho)Vg
V = F(bu)/[(rho)g]
V(f) - V(s) = [F(bu)/(rho)][1/(rhof)-1/(rhos)]
V(f) - V(s) = [37.3E3/9.8][1/(.998E3) - 1/(1.10E3)] = .354m^3

This is wrong?

Looks correct to me.

CS
 
me too
 

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