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Bouyency and Water Discplacement of 2 Fluids

  1. Sep 9, 2008 #1
    1. The problem statement, all variables and given/known data

    A boat floating in fresh water displaces water weighing 37.3 kN. What is the difference between the volume of fresh water displaced and the volume of salt water displaced (Vfresh - Vsalt)?

    F(bu) = 37.3E3 kg/m^3
    (rho)fresh water = .998E3 kg/m^3?
    (rho)salt water = 1.10E3 kg/m^3?

    2. Relevant equations

    F(bu) = m(of water displaced)g
    m(of water displaced) = (rho)V

    3. The attempt at a solution

    F(bu) = (rho)Vg
    V = F(bu)/[(rho)g]
    V(f) - V(s) = [F(bu)/(rho)][1/(rhof)-1/(rhos)]
    V(f) - V(s) = [37.3E3/9.8][1/(.998E3) - 1/(1.10E3)] = .354m^3

    This is wrong?
  2. jcsd
  3. Sep 9, 2008 #2


    User Avatar
    Science Advisor

    Looks correct to me.

  4. Sep 9, 2008 #3
    me too
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