Box on Inclined Plane (with Friction)

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SUMMARY

The problem involves a crate of mass 9.2 kg being pulled up an incline at an angle of 20.6° with a pulling force of 110 N and a coefficient of kinetic friction of 0.400. The initial speed is 1.52 m/s, and the crate is pulled a distance of 4.94 m. The calculated final speed of 10.87 m/s is incorrect because it does not account for the work done by friction and the change in kinetic energy. The correct approach requires calculating the total work done by all forces acting on the crate to determine the accurate final speed.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of work-energy principles
  • Familiarity with frictional forces and their calculations
  • Ability to apply trigonometric functions in physics problems
NEXT STEPS
  • Calculate the work done by friction using the formula F(f) = mu * N
  • Learn how to apply the work-energy theorem to find changes in kinetic energy
  • Study the effects of multiple forces on an object’s motion
  • Explore the concept of net work and its relation to final velocity
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Students studying physics, particularly those focusing on mechanics and dynamics, as well as educators looking for examples of inclined plane problems with friction.

B. variegatus
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Homework Statement


A crate of mass 9.2 kg is pulled up a rough incline with an initial speed of 1.52 m/s. The pulling force is 110 N parallel to the incline, which makes an angle of 20.6° with the horizontal. The coefficient of kinetic friction is 0.400, and the crate is pulled 4.94 m.

(e) What is the speed of the crate after being pulled 4.94 m?

Homework Equations


F(f)=mu*N
E(k)=(mv^2)/2
U=mgh
delta E(k)= E(k1) - E(k2)
W=F*d
d=(a*t^2)/2

The Attempt at a Solution


W=(m*v(f)^2)/2
v(f)=sqrt(2W/m)
W=110*4.94=543.4J
v(f)=sqrt(543.4*2/9.2)=10.87ms^-1

The computer says that this is wrong though?
 
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B. variegatus said:

Homework Statement


A crate of mass 9.2 kg is pulled up a rough incline with an initial speed of 1.52 m/s. The pulling force is 110 N parallel to the incline, which makes an angle of 20.6° with the horizontal. The coefficient of kinetic friction is 0.400, and the crate is pulled 4.94 m.

(e) What is the speed of the crate after being pulled 4.94 m?

Homework Equations


F(f)=mu*N
E(k)=(mv^2)/2
U=mgh
delta E(k)= E(k1) - E(k2)
W=F*d
d=(a*t^2)/2

The Attempt at a Solution


W=(m*v(f)^2)/2
v(f)=sqrt(2W/m)
W=110*4.94=543.4J
v(f)=sqrt(543.4*2/9.2)=10.87ms^-1

The computer says that this is wrong though?
total work is change in KE. You just gave the final,not the change. Also, more forces besides the applied force do work. You need to identify work done by all forces.
 

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