Box sliding on 35 degree grade

Click For Summary

Homework Help Overview

The problem involves a box sliding down a frictionless incline set at a 35-degree angle, with a horizontal force applied that is half the weight of the box. Participants are exploring the implications of this horizontal force on the box's acceleration.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are questioning the effect of the horizontal force on the box's motion and whether it alters the acceleration compared to a standard incline scenario. There is also discussion about the nature of the forces acting on the box, including the normal force and gravitational components.

Discussion Status

The discussion is ongoing, with participants seeking clarification on the forces involved and their interactions. Some have suggested drawing a free body diagram to visualize the forces, while others are expressing confusion about the problem's setup and the role of the horizontal force.

Contextual Notes

There is uncertainty regarding the interpretation of the horizontal force and its application, as well as the implications for the normal force and gravitational forces acting on the box.

joel amos
Messages
104
Reaction score
0
A box slides down a frictionless plane that makes an angle of 35 degrees with the horizontal. A horizontal force of half the box's weight presses the box against the plane. What is the box's acceleration?

I'm confused as to what kind of effect would a horizontal force have on an object sliding on a grade? I'm not really sure how to do this problem. Any help is appreciated. Thanks!
 
Physics news on Phys.org
I don't understand what this problem is saying, because any object you put on a frictionless 35 degree incline will always accelerate at the same rate regardless of mass. Is the horizontal force you're talking about an extra force being applied to the block by something else?
 
The posed question is the question in its entirety...and off of a test at that.
 
Start by drawing (and posting) the free body diagram.
 
Here 'tis. I wasn't exactly sure what the horizontal force was...
http://imageshack.us/a/img854/8639/problem4l.png
 
Last edited by a moderator:
The horizontal force should be applied horizontally. There will be a normal reaction force in response to this horizontal force.

mg is a force and there will be a normal reaction force to this as well.

Total of 4 forces. Your FF looks wrong. As well as your mg cosθ and mg sinθ.
 

Similar threads

Replies
4
Views
1K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 11 ·
Replies
11
Views
4K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
12
Views
3K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
8
Views
3K
  • · Replies 37 ·
2
Replies
37
Views
7K