Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Breaking RSA if you know m^k = 1 mod n

  1. Feb 5, 2011 #1
    Hello I'm looking for some guidance:
     
    Last edited: Feb 5, 2011
  2. jcsd
  3. Feb 6, 2011 #2
    You seem to assume that everyone knows what you are talking about--why?

    You certainly have not defined terms, but when I look into this, it is my impression that you have no understanding of modular arithmetic. Why not check that out?
     
  4. Feb 11, 2011 #3
    Look, RSA is built on the fact in the private key (d,n) and the public key (e,n) d and e are exponential inverses of each other mod n. If x^d or x^e are congruent to 1 then d = phi(n) or e = phi(n) respectively... Take a look at Euler's Theorem which is a generalize form of Fermat's Little Theorem. This is why in RSA there is so much care taken in picking keys.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Similar Discussions: Breaking RSA if you know m^k = 1 mod n
  1. 2^k + n (mod p) (Replies: 0)

Loading...