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Bubble sort 2D int array with c

  1. Feb 25, 2009 #1
    hi, I'm not sure if there is a homework forum for programming but I thought I'd post my problem here; I'm supposed to bubble sort a 2d integer array with elements 15 and 2; this is what my code looks like so far:

    #include <stdio.h>
    #include <stdlib.h>
    #include <time.h>

    #define cards 15
    #define sides 2

    void bubblesort(int items[cards][sides]);

    int main()
    {
    int i, stime;
    long ltime;


    ltime = time(NULL);
    stime = (unsigned)ltime/2;
    srand(stime);
    int deck[cards][sides];

    for(i=1;i<=15;i++)
    { deck[0]=i;
    deck[1]=rand();
    printf("%d ", deck[0]);
    printf("%d\n", deck[1]);
    bubblesort(deck[0]);
    }

    return 0;
    }


    void bubblesort(int items[cards][sides])
    {
    int a,b,c,d,t;

    for(a=1;a<=cards;a++)
    for(b=0;b<sides;b++)
    {
    for(c=cards-1; c>=cards;c--)
    {
    for(d=sides-1; c>=sides;d--)
    if(items[c-1][d-1] > items[c][d])
    t=items[c-1][d-1];
    items[c-1][d-1] = items[c][d];
    items[c][d] = t;
    }
    }
    }

    it keeps on returning the same 2 errors

    initializing argument 1 of void bubblesort(int (*)[2])
    and invalid conversion from int to int(*)[2]

    I'm not sure what kind of 'conversion' is going on; I've tried changing the variable array for bubblesort to pointer and to memory address but that gave extra errors; any help on what I might be doing wrong is appreciated
     
  2. jcsd
  3. Feb 26, 2009 #2
    On this line of your code
    Code (Text):
    bubblesort(deck[i][0]);
    You are sending an int to your bubblesort function, when your prototype says you are expecting a pointer to a pointer (int **). Try changing it to
    Code (Text):
    bubblesort(deck)
    But from looking at the way you have used memory, you are bound to have more problems.
     
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