Build a Pontoon: Flowtation, Weight, & Lift Calcs

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SUMMARY

The discussion focuses on calculating the flotation, weight, and lift of a pontoon measuring 30''x24''x25ft. The pontoon's volume is approximately 125 cubic feet, and its total weight is determined by the formula 125δ pounds, where δ represents the average density in pounds per cubic foot. The pontoon will displace water until the weight of the displaced water equals its own weight, with the density of water at 70°F being 62.3 pounds per cubic foot. To determine how much additional weight the pontoon can support, the equation X = (62.3)(125) - weight of pontoon is used.

PREREQUISITES
  • Understanding of buoyancy principles
  • Basic knowledge of volume calculations for rectangular solids
  • Familiarity with density measurements in pounds per cubic foot
  • Ability to solve algebraic equations related to weight and displacement
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  • Research buoyancy and Archimedes' principle
  • Learn about density calculations for various materials
  • Explore advanced pontoon design considerations
  • Investigate the effects of temperature on water density
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Marine engineers, boat builders, and hobbyists interested in pontoon design and flotation calculations will benefit from this discussion.

DAVE MCCALL
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Building a pontoon 30''x24''x25ft. How much flowtation will this give me. Weight and lift.
 
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What is the average density or total weight of the pontoon? That's the crucial point. If the pontoon is '30''x24''x25ft' or 30/12 ft by 24/12 ft 25 ft, and can be approximated by a rectangular solid, then its volume is about (5/2)(2)(25)= 125 cubic feet. If the density is \delta lbs per cubic foot, its total weight is 125\delta pounds. Assuming that the 24"= 2ft is the vertical measurement, if it sinks to a depth of d feet into the water, it will displace (5/2)(d)(25)= (125/2)d cubic feet of water.

It will sink down into the water until the weight of the water displaced, that is the volume that is the below the water times the density of water, is equal to the weight of the pontoon. The density of water, at 70 degrees fahrenheit, is about 62.3 pounds per cubic foot. So the pontoon, without any other weight on it, will sink to depth d satisfying (62.3)(125/2)d= weight of pontoon. If the pontoon is supporting an addtional weight, X pounds, then it will "just float" (sink to depth d= 2 feet so its top is just awash) with (62.3)(125)= weight of pontoon+ X so X= (62.3)(125)- weight of pontoon.

Again, you need to know either the average density of the total weight of the pontoon to find either how deep the pontoon itself will sink or what weight it will support.
 

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