Bullet trajectory: Aiming a gun

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SUMMARY

The discussion centers on calculating the correct aiming height for a shooter targeting a bird located 100 meters away, with the bullet speed set at 500 m/s. The key equations used include the maximum height formula, Hmax = (u2sin2θ)/(2g), and the range formula, R = (u2sin2θ)/g. The correct aiming height is determined to be 20 meters, highlighting the importance of understanding projectile motion and the distinction between maximum height and the aiming point.

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donaldparida
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Homework Statement

:
[/B]A person aims a gun at a bird from a point at a horizontal distance of 100m. If the gun can impart a speed of 500m/s to the bullet , then above what height of the bird he should aim his gun to hit it ?

Homework Equations

: [/B]
H_{max}=\frac{u^2\sin^2\theta}{2g}
R=\frac{u^2\sin2\theta}{g}
3. The Attempt at a Solution :

Range= R=\frac{u^2\sin2\theta}{g}\implies \sin2\theta=\frac{Rg}{u^2}\implies \sin2\theta=\frac{1}{250}\implies 2\theta=\sin^{-1}(\frac{1}{250})\implies \theta\approx 0.11Maximum height=H=\frac{u^2sin^2\theta}{2g}\implies H=0.04 mThe correct answer is 20 m. Where have i gone wrong?
 
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donaldparida said:
what height of the bird he should aim his gun to hit it ?
That is not the same as the max height reached. Draw a diagram.
 
@haruspex, Here is the diagram i drew while solving this problem,
upload_2017-6-28_15-17-39.png
 
donaldparida said:
@haruspex, Here is the diagram i drew while solving this problem,
View attachment 206195
Ok, so show on it the point above the bird that the person aims at.
 
donaldparida said:
@haruspex, Why?
If you point a gun in a certain direction, in what direction do you expect the bullet to emerge from the muzzle? What direction is that in your diagram?
 
The direction of \vec{U}?
 
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donaldparida said:
The direction of \vec{U}?
Yes. So P is a point in that line and vertically above the bird.
 

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