Insights Blog
-- Browse All Articles --
Physics Articles
Physics Tutorials
Physics Guides
Physics FAQ
Math Articles
Math Tutorials
Math Guides
Math FAQ
Education Articles
Education Guides
Bio/Chem Articles
Technology Guides
Computer Science Tutorials
Forums
Intro Physics Homework Help
Advanced Physics Homework Help
Precalculus Homework Help
Calculus Homework Help
Bio/Chem Homework Help
Engineering Homework Help
Trending
Featured Threads
Log in
Register
What's new
Search
Search
Search titles only
By:
Intro Physics Homework Help
Advanced Physics Homework Help
Precalculus Homework Help
Calculus Homework Help
Bio/Chem Homework Help
Engineering Homework Help
Menu
Log in
Register
Navigation
More options
Contact us
Close Menu
JavaScript is disabled. For a better experience, please enable JavaScript in your browser before proceeding.
You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an
alternative browser
.
Forums
Homework Help
Introductory Physics Homework Help
Understanding the Bungee Jumper Problem: Energy Transformation and Calculations
Reply to thread
Message
[QUOTE="paulimerci, post: 6832653, member: 730104"] [B]Homework Statement:[/B] Find the total energy of a 55kg bungee jumper who jumps off a bridge and comes to rest 10m above the water while the bungee with a spring constant of 25N/m is stretched 15m. [B]Relevant Equations:[/B] Total energy = 1/2 kx^2 + mgh There is a three-step energy transformation. Gravitational potential energy(GPE) is stored energy associated with an object's height above the ground. So here, the bungee jumper who is on a bridge 10m above the water has GPE. As the jumper jumps off the bridge, this stored energy is converted into K.E soon this energy will begin to be transformed into Elastic potential energy as the bungee cord is flexed to its maximum extent. Given values are m = 55kg , h = 10m, ##k = 25 \frac {N}{m}##, stretched distance = 15m, displacement (x) = stretched distance - unstretched distance = 15-10m The total energy of the system, TE, is the sum of all the different energies present in the system: TE = Elastic PE + mgh $$ TE = \frac {1}{2} kx^2 + mgh$$ $$ TE = \frac {1}{2} 25 \cdot 5^2 + 55 \cdot 9.8 \cdot 10$$ $$ TE = 5702J$$ Have I done it right? [/QUOTE]
Insert quotes…
Post reply
Forums
Homework Help
Introductory Physics Homework Help
Understanding the Bungee Jumper Problem: Energy Transformation and Calculations
Back
Top