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Understanding the Bungee Jumper Problem: Energy Transformation and Calculations
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[QUOTE="erobz, post: 6832732, member: 700856"] As far as I can tell this is what was done. Using the elevation where the jumper instantaneously comes to rest as PE = 0 They find the height ##H## of the bridge ( which is irrelevant) above PE = 0 to be given by: $$mgH = \frac{1}{2}kx^2 = \frac{1}{2} \cdot 25 \cdot 15^2 = 2812.5~\rm{J}$$ Then they must be assuming from that point they have additional 10 m gravitational potential to the water. $$ mg10 + \frac{1}{2} \cdot 25 \cdot 15^2 = 55 \cdot 9.81 \cdot 10 + \frac{1}{2}\cdot 25 \cdot 15^2 = 5395.5 ~\rm{J} + 2812.5~\rm{J} = 8208~\rm{J} $$ Not a perfect match?[ATTACH type="full" alt="IMG_1780.jpg"]318962[/ATTACH] Actually, it is a perfect match if you use 9.8 as the value for ##g## [/QUOTE]
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Understanding the Bungee Jumper Problem: Energy Transformation and Calculations
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