(volume of body)=(0,1metres)^3 (weight of body outside the barrel)=10 (weight of barrel with water without the body)=20 (weight of barrel with water and the body at the bottom)=20+10=30 Where's buoyancy? If there is buoyancy in this case, shouldn't the weight of the body inside the barrel be (weight)-(weight of displaced water)=10-1=9 and thus (weight of barrel with water and the body at the bottom)=20+9=29? By "weight" I mean what the weighing machine under the body or under the barrel shows. The weight of the body when it sits at the bottom of the barrel is 10 or 9? If we put one more weighing machine between the body and the bottom of the barrel what does it show? 10 or 9? If it shows 9, then the water+barrel weighs 21 (ignoring the weight of the "in between" weighing machine). Buoyancy is prooved by at least two other methods, but regarding when it does not sit on the bottom.