The discussion centers on the buoyancy of a submerged object in a pail of water and its effect on the total weight of the pail. When an object is hung and submerged, the tension in the string changes due to the buoyant force acting on the object. According to Newton's third law, the object exerts an equal and opposite force on the water, resulting in an increase in the weight of the pail. If the pail is full, the weight of any spilled water will equal the buoyant force acting on the submerged object, as explained by Archimedes' principle.
PREREQUISITESStudents of physics, educators teaching fluid mechanics, and anyone interested in understanding the principles of buoyancy and forces in fluids.
No. Ask yourself: Before the object is in the water, what's the tension in the string? Does that tension change when the object is submerged?darkmagic said:Well, I think it does not add. Since the object is hung? Am I correct?
Exactly.darkmagic said:before, the tension is the weight of the object. when submerged, the tension change since there is a buoyant force that acts on the object. Am I correct?
Yes.darkmagic said:So it adds weight.
No. The buoyant force isn't cancelled. But a force equal to the buoyant force will be added to the 'weight' of the pail plus water.The weight added will be the weight of the object when in air, since buoyant force will be cancelled?
If the pail starts out full to the brim, then the weight of the spilled water will exactly equal the buoyant force on the submerged object. (See Archimedes' principle.)darkmagic said:So buoyant force will be added? I got it. How about if water spills? The spilled water will be the buoyant force that will be out of the pail. However, the object exerts a force equal but opposite of the buoyant force, so it adds weight? correct?