The discussion revolves around the buoyancy effects of a submerged object in a pail of water, specifically addressing whether the weight of the pail increases when an object is submerged without spilling any water.
The discussion is active, with participants questioning and clarifying their understanding of buoyant forces and their implications on weight. Some guidance has been provided regarding the relationship between buoyant force and the weight of the pail, but no consensus has been reached on all aspects of the problem.
Participants are considering the implications of the pail being full to the brim and the effects of potential water spillage on the overall weight calculations.
No. Ask yourself: Before the object is in the water, what's the tension in the string? Does that tension change when the object is submerged?darkmagic said:Well, I think it does not add. Since the object is hung? Am I correct?
Exactly.darkmagic said:before, the tension is the weight of the object. when submerged, the tension change since there is a buoyant force that acts on the object. Am I correct?
Yes.darkmagic said:So it adds weight.
No. The buoyant force isn't cancelled. But a force equal to the buoyant force will be added to the 'weight' of the pail plus water.The weight added will be the weight of the object when in air, since buoyant force will be cancelled?
If the pail starts out full to the brim, then the weight of the spilled water will exactly equal the buoyant force on the submerged object. (See Archimedes' principle.)darkmagic said:So buoyant force will be added? I got it. How about if water spills? The spilled water will be the buoyant force that will be out of the pail. However, the object exerts a force equal but opposite of the buoyant force, so it adds weight? correct?