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Solving a Buoyancy Problem: Cube of Ice in Water & Ethyl Alcohol
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[QUOTE="Charles Link, post: 6098712, member: 583509"] The ## h ## in your 3rd to the last equation needs to be ## L=17-5-h ## to compute the volume of water that is displaced. You basically computed ## L=11.933 ##... which is how much of the cube is immersed in the water portion. ## \\ ## Edit: I read it too quickly: I was computing the ## h ## from the surface of the liquid to the top of the block. Anyway, ## L=11.93 ## mm is immersed in water, and add ## 5 ## mm to that to get their ##h ##. ## \\ ## Edit: Nope, I read it too quickly a second time: It says the surface of the water, and not the surface of the liquid. I think you may have it right, but the person who wrote out the problem didn't read his own words carefully enough. ## \\ ## Another idea: The problem could also be the sig figs in your answer. Try putting in 11.9. [/QUOTE]
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Solving a Buoyancy Problem: Cube of Ice in Water & Ethyl Alcohol
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