Buoyant Force and what densities to consider?

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SUMMARY

The discussion centers on the calculation of buoyant force (FB) in different contexts, specifically comparing submerged objects in fluids like water and hot air balloons. The correct formula for buoyant force in the case of a hot air balloon is FB = (ρin - ρout) × g × Vobject, where ρin is the density inside the balloon and ρout is the density outside. The principle of buoyancy states that the net force exerted by fluid pressure equals the weight of the fluid displaced, which applies universally to all scenarios involving buoyancy. The net upward force can be expressed as F = ρgV - mg, where ρ is the density of the fluid, V is the volume displaced, and mg is the weight of the object.

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Ian Baughman
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So I know

FB = ρDF × g ×VDF
when we submerge an object in a fluid such as water but what if we were talking about a hot air balloon? In this case would it be correct to use

FB = (ρin - ρout) × g ×Vobject?​

Where
ρin = density inside balloon and ρout = density outside balloon.
If this is the case how do we know when to differentiate between the two?
 
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Your two equations appear to be using different definitions for "buoyant force"...

The rule is that the fluid-pressure exerts a net force equal to the weight of the fluid displaced ... if this is bigger than the weight of the object, it rises.

That rule works for all situations... don't bother memorising any specific equation, you already know all the ones you need.

The weight of fluid displaced is ##\rho V g## (V is the volume displaced, and ##\rho## is the density of the fluid)
The weight of the object is ##mg##
... so the net upwards force is ##F=\rho g V - mg##

If all the object is in the fluid, then I can write ##m = \rho_mV## since the volume displaced is the same as the volume of the object
... which gives: ##F = (\rho-\rho_m)gV##
... which only works for the case that the entire object is immersed in the fluid.
 

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