Burning fossil fuels math problem

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Homework Help Overview

The problem involves estimating the total mass of fossil fuels burned annually based on energy consumption figures. It is situated within the context of energy conversion and mass-energy relationships, specifically focusing on fossil fuel energy content.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the conversion of energy units from EJ to MJ and the relevance of time units in the problem. There is uncertainty about whether to convert annual energy consumption into a per-second basis. Some participants question the necessity of this conversion, while others suggest it simplifies the calculations.

Discussion Status

There is an ongoing exploration of the relationship between energy content and mass of fossil fuels. Some participants have provided guidance on unit conversions and calculations, while others express confusion about the next steps and how to reconcile different results.

Contextual Notes

Participants note the discrepancy between their calculations and the textbook answer, leading to discussions about unit conversions and the interpretation of mass in different contexts. There is also a second part of the problem regarding the transportation of fuel, which introduces additional complexity.

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Homework Statement



Humankind uses about 500 EJ of energy each year nearly all of it from fossil fuels. If the energy content of fossil fuels is 40 MJ/kg estimate the total mass of fossil fuels we burn each year.

Homework Equations



I am not sure if this is a relevant equation but in my textbook there is a similar example showing the energy content of divided by the total thermal power extracted measured in MJ/kg

The Attempt at a Solution



I really don't know if I'm doing any of this right but I thought I needed to convert the 500 EJ into MJ. I got 5 x 10^14.

This problem is talking about a year while the textbook shows per second. Do I need to convert to seconds in a year? If so i got 31, 536,000 seconds. Not sure if I even needed to do this...

I have no idea if I even started this problem right or where to go from here if I have?
 
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courtneywetts said:

The Attempt at a Solution



I really don't know if I'm doing any of this right but I thought I needed to convert the 500 EJ into MJ. I got 5 x 10^14.

This problem is talking about a year while the textbook shows per second. Do I need to convert to seconds in a year? If so i got 31, 536,000 seconds. Not sure if I even needed to do this...

I have no idea if I even started this problem right or where to go from here if I have?
The conversion is done right, And it was necessary to do that. It doesn't matter if the answer comes out in years or seconds, it would be the same. But since the textbook has the answer in terms of seconds it is better to do it that way.
Now given that human kind consumes 5×1014MJ per 31,536,000 seconds what would be the consumption for 1 second?
To find out the amount of fossil fuel consumed:
40 MJ of the energy is got by 1kg of the fuel, how much for X MJ (the answer you have got from above)
Regards
 
courtneywetts said:
This problem is talking about a year while the textbook shows per second. Do I need to convert to seconds in a year?
Converting to seconds is making the problem much more complicated than necessary. You know how many MJ a year are generated, and you know how many MJ are generated by 1 kg. It's a very simple operation to determine the number of kgs/year.
 
haruspex said:
Converting to seconds is making the problem much more complicated than necessary. You know how many MJ a year are generated, and you know how many MJ are generated by 1 kg. It's a very simple operation to determine the number of kgs/year.

If there are 5 x 10 ^14 MJ in a year and 40 MJ/kg then would I just divide?
 
courtneywetts said:
If there are 5 x 10 ^14 MJ in a year and 40 MJ/kg then would I just divide?

Yes.
 
haruspex said:
Yes.

I did this and got 1.24 x 10 ^13 kg/yr.

The answer in the back of the book is 12 billion tones/yr.

I am not sure how this answer was gotten... or what step I would need to do next to get this answer.
 
1 tone= 1000 kg
1 billion = 10^9 (in the US).
 
nasu said:
1 tone= 1000 kg
1 billion = 10^9 (in the US).

I am confused as to what I am supposed to do with this?
 
To show that the two results are the same (pretty much).
 
  • #10
The second part of this question says assume that each kilogram of fuel has to be move 1000 km from its source to where it's burned at an average speed of 20 km per hour. Estimate the total mass of fuel that must be in transit at a given time.

I am not sure how to start this problem...or what formula to use.
 
  • #11
courtneywetts said:
The second part of this question says assume that each kilogram of fuel has to be move 1000 km from its source to where it's burned at an average speed of 20 km per hour. Estimate the total mass of fuel that must be in transit at a given time.

I am not sure how to start this problem...or what formula to use.
How long does each bit of fuel spend moving? How many kg must reach their destination in that time?
 
  • #12
haruspex said:
How long does each bit of fuel spend moving? How many kg must reach their destination in that time?

I really don't know what you mean by this. What number should I be starting with?
 

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