Cable friction and tension problem

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SUMMARY

The discussion centers on the principles of tension in a massless pulley system, specifically referencing example 2 from the provided link. It establishes that the tensions labeled as T are equal due to the nature of cables and strings, which maintain uniform tension throughout. The conversation clarifies that while torque is present, it cancels out because of the equal tensions and the absence of friction in the system. Additionally, it emphasizes that any initial difference in tension quickly equilibrates along the cable.

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Read please example 2 of http://cnx.org/content/m14060/latest/ .

P1
fap6.gif


P2
fap7.gif


On picture 2 there are those two tension labeled by T which are equal. Why equal?

And shouldn't they exert just torque? I know we are considering the pulley to be massless, so no torques. So is it correct to consider those two tensions applied at the center of mass of the pulley?

Thanks in advance for your clarification. :smile:
 
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The cable has to have the same T, because that is the nature of strings and cable. It is irrelevant where you applie them. The magnitude and direction matter. There is torque on the pulley, but they cancel out.
 
That is because thay are the same cable and there is supposedly nor friction in the system. You might, for an instant initially get tension which is different from the other but you can imagine that the tension is 'transferred' along the cable until they are equal.
 

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