Consider there is a 634 N weight held by two cables that meet at a point above the weight. The left cable with tension T sub 2 makes an angle of 46° to the horizontal. The right cable with tension T sub 1 makes an angle of 40° to the horizontal.
a) What is the tension in the cable labeled T sub 1 slanted at an angle of 40°?
b) What is the tension in the cabel labeled T sub 2 slanted at an angle of 46°?
I feel that the only relevant equation in this case is that the Tension always equals the Force. Therefore F sub T would equal the weight.
The Attempt at a Solution
I attempted to logically conclude that by splitting each tension force into components, the x components of each would have to equal 0 to balance each other out. I also thought that the y components of each would have to be equal to each other since they are the same height. So I had the equations Tsub1xsin40+Tsub2xsin46=634. I also had that Tsub1xcos40-Tsub2xcos46=0. Then I solved the second equation for Tsub1 and plugged it into the first equation and solved, but the answer was wrong. Help?