Calc Fall of Object from Space: Derive Eqn of Accel as Fxn of Time

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Homework Help Overview

The discussion revolves around calculating the distance from which an object falls to Earth, given a fall time of 17.5 hours. The problem involves deriving an equation for acceleration as a function of time, considering the object's initial speed is zero.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between acceleration, distance, and time, questioning how to derive velocity as a function of distance and subsequently time. Some suggest using differential equations to relate these variables, while others express uncertainty about solving these equations.

Discussion Status

Participants are actively engaging with the problem, offering various approaches to derive the necessary equations. There is a focus on understanding the relationship between acceleration and distance, as well as the implications of using differential equations. No consensus has been reached yet, but several lines of reasoning are being explored.

Contextual Notes

Some participants note their limited experience with calculus and differential equations, which may affect their ability to engage with the problem fully. The discussion also highlights the challenge of transitioning from problems involving acceleration as a function of time to those involving distance.

recon
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If it takes an object at distance x from the surface of the Earth 17.5 hours to fall from space onto the surface of the Earth, how can we calculate x? The object initially has zero speed.

I find this question hard because I've only done problems involving acceleration as a function of time, and not as a function of distance. :redface: Can anyone show me how to derive an equation of acceleration as a function of time?
 
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recon said:
If it takes an object at distance x from the surface of the Earth 17.5 hours to fall from space onto the surface of the Earth, how can we calculate x? The object initially has zero speed.
I find this question hard because I've only done problems involving acceleration as a function of time, and not as a function of distance. :redface: Can anyone show me how to derive an equation of acceleration as a function of time?

You can use [tex]\frac{dv}{dt} = (\frac{dv}{dr})(\frac{dr}{dt}) = v \frac{dv}{dr}[/tex]
So I think from this you can first find v(r) and then r(t) and use that to find x.
 
The first thing you may want to realize is that acceleration is a function of distance between the object and the center of the earth, and that the distance is a function of time.
 
siddharth said:
You can use [tex]\frac{dv}{dt} = (\frac{dv}{dr})(\frac{dr}{dt}) = v \frac{dv}{dr}[/tex]
So I think from this you can first find v(r) and then r(t) and use that to find x.
I know [tex]\frac{dv}{dt} = \frac{GM}{r^2}[/tex] but I can't figure out how this may be used to obtain v as a function of r.
How is it possible to solve the equation [tex]\frac{d^{2}r}{dt^2}=\frac{GM}{(R+r)^2}[/tex], where R is the radius of the Earth? I have not had much calculus yet, so I have not touched on solving differential equations of this difficulty.
 
Last edited:
You have

[tex]\frac{dv}{dt} = \frac{GM}{r^2}[/tex]

Now, as I said in my previous post,

[tex]\frac{dv}{dt} = (\frac{dv}{dr})(\frac{dr}{dt}) = v \frac{dv}{dr}[/tex]

So,
[tex]v\frac{dv}{dr} = \frac{GM}{r^2}[/tex]

Now, can you find v(r) from this diff equation?
 

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