Calc Vertice Problem: Finding the Closest Point in an Ellipse to a Focus

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SUMMARY

The discussion centers on the geometric properties of ellipses, specifically identifying the closest point (vertex) to a focus. In the equation \(\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\), where \(a > b > 0\), the vertex at (a,0) is confirmed as the closest point to the focus located at (c,0). Additionally, the vertex at (-a, 0) is recognized as the farthest point from the focus. A clarification is made regarding the terminology, noting that the correct singular form is "vertex," not "vertice."

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flyingpig
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Homework Statement



One vertice is the closest point to a focus in an ellipse. For instance take

[tex]\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1[/tex] with a > b > 0 and one focus at (c,0) and one vertice at (a,0), is (a,0) the closest point on the ellipse to the focus (c,0)?


2. The attempt at a solution

This is true right?
 
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Yes, that is true. And the other vertex, (-a, 0) is the point farthest from the focus.

By the way, the singular of "verices" is "vertex", not "vertice".
 

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