Calculate a: Dist. b/w Lens Positions for 40 cm Object-Image Distance

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SUMMARY

The discussion focuses on calculating the distance between two positions of a converging lens with a focal length of 3.62 cm, given a fixed object-image distance of 40.0 cm. The thin lens formula, represented as 1/f = 1/o + 1/i, is utilized to derive the two lens positions that yield a sharp image. By manipulating the object distance (o) and image distance (i), participants clarify that the sum of these distances must equal 40 cm, leading to the determination of the distance 'a' between the two lens positions.

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matt85
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The distance between an object and its image is fixed at 40.0 cm. A converging lens of focal length f = 3.62 cm forms a sharp image for two positions of the lens. What is the distance a between these two positions?

Determine:

The distance between these two positions a = ____cm

Could someone help me with the formula i want to be using?
 
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The thin lens formula gives
[tex]\frac{1}{f}=\frac{1}{o}+\frac{1}{i}[/tex]
with i the image distance and o the object distance. Now say you find a position between the object and fixed screen (image position) such that you get a sharp image on the screen. The object image is now o and the image distance i while the sum of these two being 40 cm. But according to the formula if you make the object distance i the image distance should be o! Which gives you the other position of the lens where you should get a sharp image on the screen. In the second case the object distance will therefore be i and the image distance will be o.
 
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I would guess that with a mech advantage of 2 you would have problems lifting your lecturer! Three would give you a fighting chance!
 

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