Calculate Acceleration of Thrown Baseball: 5.98s, 1.2m from Rest

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The discussion focuses on calculating the acceleration of a baseball thrown straight up, which remains airborne for 5.98 seconds and travels a distance of 1.2 meters from rest. To determine the acceleration produced by the thrower's arm, one must first calculate the initial velocity required for the ball to stay in the air for the specified duration using kinematic equations. The final step involves applying the formula for constant acceleration to find the acceleration over the distance of 1.2 meters.

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A person throws a baseball straight up (in the y direction). The ball is in the air for 5.98 seconds before it returns to the same height from where it was initially released. If the person when throwing the ball, generated a constant acceleration over a distance 1.2 m from rest, what is the acceleration produced by the person's arm in m/s2?

I guess you have to use a constant acceleration equation or a free fall equation, but I do not know which one.
 
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First of all find the initial velocity with which the ball is thrown up so that it will be in the air for 5.98 seconds.
Then find the acceleration of the arm which can produce this velocity with in the distance of 1.2 m.
 
Check out this link, it may help you------>media.wiley.com/product_data/excerpt/88/.../0471713988.pdf
 

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