Calculate air-flow using pressure drop

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SUMMARY

This discussion focuses on calculating air flow from a pressurized outlet using pressure drop measurements. Key concepts include the application of Bernoulli's equation for flow velocity calculations, particularly in scenarios involving orifices or valves. The conversation highlights the importance of understanding pressure differences and the complexities introduced by factors such as gas density changes and potential choked flow conditions. Participants emphasize the need for precise data regarding pressure levels to derive accurate flow rates.

PREREQUISITES
  • Bernoulli's equation for fluid dynamics
  • Understanding of pressure drop and flow velocity
  • Knowledge of compressible flow principles
  • Familiarity with gas dynamics and choked flow conditions
NEXT STEPS
  • Research compressible flow equations for high-pressure scenarios
  • Explore Milton Beychok's resources on gas release calculations
  • Study the effects of viscosity on gas flow in various geometries
  • Learn about the implications of choked flow in pressurized systems
USEFUL FOR

Engineers, fluid dynamics specialists, and anyone involved in designing or analyzing pressurized gas systems will benefit from this discussion.

apekattenico
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At what speed (flow/volume for that matter) does air leave an outlet when you know it holds x bars in the pipe?

(It goes from x to zero (or athmospheric) -- you know the pressure difference)

I assume you can neglect relative roughness, resistance, and so on as the pressure drop is over such a short distance they do not affect it. The only thing that matters is the size of the hole. Am I in the wrong here?

How would I calculate such a thing?

Thanks for any answer :)
 
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How do you know the pressure drop? Just because it vents to atmosphere doesn't mean the gage pressure immediately goes to zero. I don't think we have enough information to give an easy answer.
 
apekattenico said:
At what speed (flow/volume for that matter) does air leave an outlet when you know it holds x bars in the pipe?
I don't think that you (can) even know that. The upper limit for gas speed in a pipe is the local 'speed of sound'. Continuity suggests that speed goes to zero as flow area goes to infinity. But 'speed of sound' is very complicated and your question is intimate with the design of rocket motor's bells.

Don't think of pressure (force per area) but use mole rate, moles per time.

I was given a facility where I directed operations. One was to pressurize a large tank as quickly as possible. It was challenging to explain/convince the operators that once the adjustable pressure regulator was squealing there was no point increasing the desired pressure. The squeal was the shock wave of the gas at the local speed of sound.
 
Brian_C said:
Just because it vents to atmosphere doesn't mean the gage pressure immediately goes to zero.
Actually, for all intents and purposes, it does.

apekattenico, you haven't given us much to go on, but if you have an orifice (such as a slightly opened valve where you can be certain virtually all of the pressure drop occurs, then you can simply apply Bernoulli's equation to calculate the flow veloctiy (up to a few hundred feet per second).
 
Brian_C said:
How do you know the pressure drop? Just because it vents to atmosphere doesn't mean the gage pressure immediately goes to zero. I don't think we have enough information to give an easy answer.


Doug Huffman said:
I don't think that you (can) even know that. The upper limit for gas speed in a pipe is the local 'speed of sound'. Continuity suggests that speed goes to zero as flow area goes to infinity. But 'speed of sound' is very complicated and your question is intimate with the design of rocket motor's bells.

Don't think of pressure (force per area) but use mole rate, moles per time.

I was given a facility where I directed operations. One was to pressurize a large tank as quickly as possible. It was challenging to explain/convince the operators that once the adjustable pressure regulator was squealing there was no point increasing the desired pressure. The squeal was the shock wave of the gas at the local speed of sound.

Fair point, but I think you are over complicating things.

russ_watters said:
Actually, for all intents and purposes, it does.

apekattenico, you haven't given us much to go on, but if you have an orifice (such as a slightly opened valve where you can be certain virtually all of the pressure drop occurs, then you can simply apply Bernoulli's equation to calculate the flow veloctiy (up to a few hundred feet per second).


And I did so on purpose.

I might be in the wrong here, but allow me to explain how I think, and feel free to correct me.

The difference in pressure causes a net force, which drives the air forward.

Given a pressure difference it's critical to understand where you get it. p1 is inside the pipe at speed v1, while p2 is outside at speed v2 (which must be 0 as p2 equals zero. (this might very well be incorrect)

When I open a valve on the pipe there excists a pressure difference over the pipe which makes the air move forward.

I believe you might very well apply The Bernoulli equation (imagine two cross sections - one before, and one after)

Is my logic flawed, or can I go with this?

EDIT:
To give some context.
I'm interested in checking how much air-leakage costs. Yes, I can find data on this other places, but I want to know if these are rough estimates (just like my calculation will be), or they have done it in detail.

But then again I do know that this problem is highly nonlinear coupled problem (the gas is cooling, the pressure is changing, and the flow rate may or may not be choked flow, etc...).

Are there any easy ways out here?
 
Last edited:
russ_watters said:
Actually, for all intents and purposes, it does.

apekattenico, you haven't given us much to go on, but if you have an orifice (such as a slightly opened valve where you can be certain virtually all of the pressure drop occurs, then you can simply apply Bernoulli's equation to calculate the flow veloctiy (up to a few hundred feet per second).

How can you apply Bernoulli's equation? He's talking about a pressure difference of several atmospheres. The density of the gas will change dramatically. Viscous forces could also have a significant impact depending on the flow geometry.
 
For times like this, I always reference people to Milton Beychok's web site. He has some really good stuff for calculating the accidental release of gasses under pressure and I think this is applicable now. It's mostly compressible flow equations that should look familiar.

http://www.air-dispersion.com/usource.html
 
Good link. Thanks FredGarvin.

Matt
 
Brian_C said:
How can you apply Bernoulli's equation? He's talking about a pressure difference of several atmospheres. The density of the gas will change dramatically. Viscous forces could also have a significant impact depending on the flow geometry.
I'm not sure - he just said "x" bars and I don't know what that means. If it's 2 or 3, the simple form of Bernoulli's still works pretty well. If it's 5-10 you need compressibility and viscocity effects. If it's 10 or 20, you get choked flow. I guess this is where the "need more info..." bit comes in.
 
  • #10
It appears that American engineering language is not the OP's forte and that he knows more than we do about the question at hand.
Fair point, but I think you are over complicating things.
 

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