Calculate Angles Between Planes in 3D Space

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To calculate the angle between the two planes defined by the equations 2x+y-3z+7=0 and 4x-y+7z+5=0, one must first determine the normal vectors of each plane. The normal vector can be extracted from the coefficients of x, y, and z in the plane equations. The angle between the two planes is equivalent to the angle between their normal vectors, which can be calculated using the dot product formula. It is important to note that there is only one angle to consider, although the supplementary angle can also be derived. Understanding these concepts is crucial for accurately calculating the angle between the planes.
blimkie
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calculate the angles bewteen of the intersection of the planes:
2x+y-3z+7=0 and 4x-y+7z+5=0

any takers? i just need an idea of where to start

thanks
 
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Do you know how to find the normal vectors for the two planes?
Do you know how to find the angle between two vectors?

Do you see why the angle between the two vectors is the angle between the planes?
(Oh, and there is only one angle, not "angles".)
 
Well there is always the supplementary angle too of course, but if you have one, the difference between pi and that angle is the other one.
 
Just to add:

a(x-x_0)+b(y-y_0)+c(z-z_0)=0

is the general equation of a plane. The vector <a,b,c> is the normal vector to that plane. Can you see where to get a, b, and c from your original planes?

Alex
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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