Calculate consumption, displacement and speed using given standards

[Sophie87]

Homework Statement

Calculate consumption, displacement and speed using given standard values in pneumatic cylinders and pipes (ISO 155552 Standard and ANSI B31.3 Standard).

I've been given three tables on different standards in pneumatics and the following values:

Force of advance= 50 kgf

Total Displacement: 3cm

Displacement: 45 seconds

Normal atmospheric conditions include Tn= 20 degrees Celsius and Pn= 1.03 kgf/cm2

The temperature of operation: 10 degrees above the environment temperature (dry-bulb)

From the table of unit consumption, calculate the total consumption and the discharge demanded by the cylinder. Speed of the air in the pipes: as per standards. Speed of the air in the hoses: as per standards. Calculate the diameters of the pipe and hoses. Select the most appropriate standardized piping based on the calculated diameter.

Relevant Equations

kgf/cm^2 = 50/(3^2) = 5.6 rounded up.

I calculated the value of kgf/cm^2 from given values. In the second table (Force exerted by the pneumatic cylinders) I see my value 5.6 exactly but how do I then read the table to get the diameter of the cylinder and then the rod?

I then am stuck on how to calculate the total consumption, displacement and speed of cylinders, pipes and hoses as I didn't learn this in class.

Can anyone help explain this for me?

Below are images of the table standards:

 

[Sophie87]

I think I've worked out that my total consumption is 4 dm³. Is this right? By:

50/(3^2)= 5.555555...6= 5.6 rounded up. For kgf/cm^2

Using force exerted by the pneumatic cylinders table...
Pressure will then be 80 psi.
Pressure/Force= 80/5.6= 14.28571429= 14.3 rounded up. (To get the area of the cylinder!)
The closest force exerted is 64 kgf.
So the diameter of the cylinder will be 1 1/2".

Then using the ISO Standard table...
So the diameter of the rod will be 5/8".
So then I will take 3cm and cube it to make 9 cm^3. I will then transfer that to dm^3 which will be 0.009 dm^3. Closest value is 0.010, which equals to 4 dm^3 of air consumption.

 

[Sophie87]

I still don't know about displacement or speed! So if anyone could help explain these that would be great!