Calculate Current in Nichrome Wire with 11V Voltage

[BuBbLeS01]

[SOLVED] More Current...please help me!

Homework Statement

A 11 V potential difference is applied between the ends of a 0.89-mm-diameter, 42.49-cm-long nichrome wire. What is the current in the wire?

Homework Equations

I = Ch in V / R

The Attempt at a Solution

How do I find R?

 

[BuBbLeS01]

nevermind I am retarded

 

[Moetasim]

To find the resistance (R) of the wire, we can use the formula R = ρL/A, where ρ is the resistivity of nichrome wire, L is the length of the wire, and A is the cross-sectional area of the wire. The resistivity of nichrome wire is typically around 1.5 x 10^-6 Ωm. Using the given diameter and length of the wire, we can calculate the cross-sectional area as A = π(0.89 x 10^-3 m)^2 / 4 = 6.23 x 10^-7 m^2. Plugging these values into the resistance formula, we get R = (1.5 x 10^-6 Ωm)(42.49 x 10^-2 m) / 6.23 x 10^-7 m^2 = 1.02 Ω.

Now, we can use the formula I = V/R to calculate the current (I) in the wire. Plugging in the given voltage of 11 V and the calculated resistance of 1.02 Ω, we get I = (11 V) / (1.02 Ω) = 10.8 A. Therefore, the current in the nichrome wire with a 11 V potential difference is approximately 10.8 A.