Current in a hollowed nichrome wire

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SUMMARY

The current in a hollow nichrome wire connected to a 2.50 V battery is calculated to be 277 A. The wire has a length of 10.0 cm, an inner diameter of 2.20 mm, and an outer diameter of 5.10 mm. The resistance is determined using the formula R = ρ*(L/A), where ρ is the resistivity of nichrome (1.5E-6 ohm-meters). The calculations reveal that the resistance R is 0.00902 ohms, leading to the derived current I using Ohm's Law (V = IR).

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Minhtran1092
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Homework Statement



A 10.0 cm long hollow nichrome tube of inner diameter 2.20 mm , outer diameter 5.10 mm is connected to a 2.50 V battery. What is the current in the tube?

Homework Equations


V=IR
R = p*(L/A);p = resistivity of nichrome (1.5E-6), L = length of wire, A = Surface area of cross section


The Attempt at a Solution


V = I*R → V/R = I; V = 2.5V
R = p*(.1cm)/(π([5.1/2]/1000))2)-π((1.1/1000)2))

I = 2.5/R; Isn't correct
 
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Looks good to me, you must have done some calculations wrong... If you used wolframalpha or similar, your brackets are wrong so that might have messed it up...

I got R=0.00902 ohms, I=277 A
 

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