Hydraulic lift diameter of larger piston with 500N force on smaller piston

[bcddd214]

Homework Statement

A hydraulic lift raises a 3000 kg car when 500 N force is applied to the smaller piston. If the smaller piston has an area of 10 〖cm〗^2, what is the diameter of the larger piston?

Homework Equations

p_1=p_2
F_1/A_1 =F_2/A_2
A_2=(F_2 A_1)/F_2
A=πr^2
r=d/2

The Attempt at a Solution

monkey/lightbulb=me from here

 

[ideasrule]

Do you know what all of your relevant equations mean? You have more than enough to solve the problem. Specifically, look at F_1/A_1 =F_2/A_2. Let's say that A_2 is the area of the smaller piston, 10 cm^2. You're trying to find A_1, because after that, you can easily get the diameter. What's F_2, the force on the smaller piston? How about F_1, the force on the larger piston?

 

[ZealScience]

The basic rule for this type of question is that pressure is constant at the same level. I think if the height of water level is the same, then it is fairly straight forward.