# Forces and Pressure in a Hydraulic System

1. Dec 8, 2011

### forestmine

1. The problem statement, all variables and given/known data
The small piston of a hydraulic lift has a diameter of 8.0 cm, and its large piston has a diameter of 40 cm. The lift raises a load of 15,000 N.

(a) Determine the force that must be applied to the small piston.

(b) Determine the pressure applied to the fluid in the lift.

2. Relevant equations

p=F/A

3. The attempt at a solution

I correctly solved for part a, and came up with an answer of 600 N. I'm a little unclear about how to obtain the answer for part b. My thought was that since pressure = F/A, I could simply take the pressure I found from part a, and divide by the area of the smaller piston, but I'm not getting the correct answer...

2. Dec 8, 2011

### obafgkmrns

You're doing it correctly. Could the problem be one of units? Pressure is often stated in newtons/meter^2 (i.e., pascals). Note that 8.0 cm = 0.08 m.

3. Dec 8, 2011

### forestmine

EDIT// I must have been making a calculation error. I figured it out.

Thank you!

Last edited: Dec 8, 2011