Master and Output Pistons in Car Breaking System: Calculating Force and Movement

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SUMMARY

The discussion focuses on calculating the output force and movement of pistons in a car braking system, specifically using a master piston with a diameter of 10 cm and four output pistons with a diameter of 2 cm each. When a force of 500 N is applied to the master piston, the output force on each wheel piston is determined using the principle of hydraulic systems, which states that pressure is constant throughout the system. The movement of the output pistons is calculated based on the ratio of the areas of the pistons, leading to a movement of 25 cm for each output piston when the master piston moves 5 cm.

PREREQUISITES
  • Understanding of hydraulic systems and Pascal's principle
  • Knowledge of pressure calculation using the formula: Pressure = Force / Area
  • Familiarity with the concept of piston area ratios
  • Basic principles of fluid mechanics
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  • Study hydraulic systems and their applications in automotive engineering
  • Learn about pressure calculations in fluid mechanics
  • Explore the relationship between force, area, and movement in hydraulic systems
  • Investigate the implications of energy conservation in hydraulic systems
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This discussion is beneficial for automotive engineers, mechanical engineering students, and anyone interested in understanding the principles of hydraulic braking systems and force transmission in automotive applications.

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Homework Statement



the breaking system on a car utilises a master pistion that is 10 cm in dimeter. the four outout pistons (one on each wheel) are 2cm in diameter

a) if 500 N of force is applied to the master piston, what is the output force on each of the wheel pistons?

b) if the master piston moves 5cm, how much does each output piston move?

c)how is this not a free lunch?


Homework Equations



unknown. missed class the day this was done and I cannot foind an example like it.



The Attempt at a Solution



I figured that the force would just be divided by four but looking at C that must not be right or that wouldn't be there.

b) for the output piston i would think it would be 10/2 x 5= 25 cm. but I am not sure about this answer.
 
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Think in terms of pressures transmitted by the working fluid from and to the piston surface areas. Consider the pressure in the working fluid to be everywhere the same. Also consider that the total volume of working fluid is constant.
 


i still don't get it, what is the formula for it, could you show me a sample calculation?
 


What is the pressure in the working fluid if a 500N force is applied to the 10cm diameter piston? (hint: what is the formula for pressure given force and area?).
 

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