Calculate distance from force HELP

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SUMMARY

The discussion focuses on calculating the distance traveled by a probe in outer space under a constant net force of 135N. The initial calculation using F=Ma yielded an acceleration of 4.47 m/s². To find the distance traveled in 6.00 seconds, the correct formula used was X = vt + 0.5(a)(t)², leading to a final distance of 80.46 meters. This method highlights the importance of using the appropriate kinematic equations for motion under constant acceleration.

PREREQUISITES
  • Understanding Newton's Second Law (F=Ma)
  • Familiarity with kinematic equations for uniformly accelerated motion
  • Basic knowledge of units of force, mass, and acceleration
  • Ability to perform algebraic manipulations and solve equations
NEXT STEPS
  • Study kinematic equations in detail, particularly X = vt + 0.5(a)(t)²
  • Learn about the implications of force and acceleration in different environments, such as outer space
  • Explore practical applications of Newton's laws in aerospace engineering
  • Investigate the effects of varying forces on motion and how to calculate resultant distances
USEFUL FOR

Students in physics, aerospace engineers, and anyone interested in understanding motion under constant forces in a vacuum.

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Calculate distance from force HELP!

In outer space, a constant net force of magnitude 135N is exerted on a 30.2kg probe initially at rest. What acceleration does this force produce? How far does the probe travel in 6.00s

what i have so far is that F=Ma
where the force is 135N=30.2a solve for a and get 4.47m/s.

now this is where i get lost. to find the distance I am assuming that it travles 4.47m/s so the gerneal idea i got was to multiply by 6.00s and get 26.82m. This answer is incorrect anyone have any ideas?
 
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ok i got it i figured it out
i had to use a seperat equation where X=volt + .5(a)(t)^2

x=0(6)+ .5(4.47)(6)^2
solve all that for X and i got 80.46 m and this answer is correct.
 

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